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Electric Field Magnitude
8,987.55
newtons per coulomb (N/C) = volts per meter (V/m)
Force per unit charge 8,987.55 N/C
Coulomb constant k 8.9875517873681764 × 10⁹ N·m²/C²

What is the Electric Field Calculator?

This tool computes the magnitude of the electric field produced by a single point charge at a given distance. It uses Coulomb's law in field form, \(E = kQ/r^{2}\), where the result is expressed in newtons per coulomb (N/C), which is numerically identical to volts per meter (V/m). The calculator is universal physics and applies anywhere.

How to use it

Enter the source charge Q in coulombs (use scientific quantities like 0.000001 for 1 µC) and the distance r in meters from the charge to the point where you want the field. Press calculate to read the field strength. A positive charge gives a positive (outward) field; a negative charge gives a negative value indicating the field points toward the charge.

The formula explained

The electric field of a point charge falls off with the square of distance: $$E = \frac{kQ}{r^{2}}$$ Here \(k \approx 8.9876 \times 10^{9}\ \text{N}\cdot\text{m}^{2}/\text{C}^{2}\) is Coulomb's constant, Q is the charge in coulombs, and r is the separation in meters. Doubling the distance reduces the field to one quarter of its value.

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Curve showing electric field strength decreasing with the square of distance
Field strength E falls off as \(1/r^{2}\), dropping sharply as distance increases.
Point charge with radial electric field lines and distance r to a point P
The electric field of a point charge radiates outward, weakening with distance r.

Worked example

For a charge of \(Q = 1 \times 10^{-6}\ \text{C}\) (1 µC) at \(r = 1\ \text{m}\): $$E = \frac{8.9876 \times 10^{9} \times 1 \times 10^{-6}}{1^{2}} \approx 8{,}987.55\ \text{N/C}$$ At \(r = 2\ \text{m}\) the field drops to about 2,246.89 N/C — one quarter as strong.

FAQ

What are the units of E? Newtons per coulomb (N/C), equivalent to volts per meter (V/m).

Why is my result negative? A negative source charge produces a field directed toward the charge; the sign indicates direction along the radial line.

Does distance zero work? No — the field diverges at \(r = 0\), so the calculator returns 0 to avoid dividing by zero. Use a non-zero distance.

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