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Formula

Formula: Temperature Conversion Calculator
Show calculation steps (1)
  1. Celsius to target

    Celsius to target: Temperature Conversion Calculator

    Then convert Celsius to the target scale: F = Cx9/5+32, K = C+273.15, R = Cx9/5+491.67, Re = Cx4/5.

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Results

50 °C =
122
°F (Fahrenheit)
From 50 °C (Celsius)
Via Celsius 50 °C
To 122 °F (Fahrenheit)

What this calculator does

This tool converts a temperature value between any two of five temperature scales: Celsius (°C), Fahrenheit (°F), Kelvin (K), Rankine (°R), and Reaumur (°Re). It is a pure physics unit conversion, so the results are identical everywhere in the world with no regional rules or assumptions involved.

Five thermometer scales aligned by freezing and boiling points of water
The five temperature scales compared at water's freezing and boiling points.

How to use it

Choose the scale you are converting From, choose the scale you want to convert To, and type the temperature in the Value to Convert field. Negative values are allowed (for example -40, or any sub-zero Celsius reading). Press calculate to see the answer along with the intermediate Celsius value. If you pick the same scale for From and To, the value is returned unchanged.

The formula explained

The calculator uses Celsius as a pivot. Step 1 converts your input into Celsius: from Fahrenheit, \(^{\circ}C = (^{\circ}F - 32) \times \tfrac{5}{9}\); from Kelvin, \(^{\circ}C = K - 273.15\); from Rankine, \(^{\circ}C = (^{\circ}R - 491.67) \times \tfrac{5}{9}\); from Reaumur, \(^{\circ}C = {}^{\circ}Re \times \tfrac{5}{4}\). Step 2 converts that Celsius value into the target scale: $$^{\circ}F = {}^{\circ}C \times \tfrac{9}{5} + 32$$ \(K = {}^{\circ}C + 273.15\); \(^{\circ}R = {}^{\circ}C \times \tfrac{9}{5} + 491.67\); \(^{\circ}Re = {}^{\circ}C \times \tfrac{4}{5}\). Using exact fractions (\(\tfrac{9}{5}\), \(\tfrac{5}{9}\), \(\tfrac{4}{5}\), \(\tfrac{5}{4}\)) avoids rounding drift. These scales are affine (multiply and add) because their zero points differ - Kelvin and Rankine start at absolute zero, while Reaumur sets water freezing at 0 and boiling at 80.

Linear relationship between Celsius and Fahrenheit with slope nine fifths and intercept thirty-two
Celsius-to-Fahrenheit is a straight line with slope 9/5 and offset 32.

Worked example

Convert 50 °C to °F. Step 1: the input is already Celsius, so \(^{\circ}C = 50\). Step 2: $$^{\circ}F = 50 \times \tfrac{9}{5} + 32 = 90 + 32 = 122$$ Therefore 50 °C = 122 °F. As another check, 80 °Re converts to \(^{\circ}C = 80 \times \tfrac{5}{4} = 100\,^{\circ}C\), which is \(100 \times \tfrac{9}{5} + 32 = 212\,^{\circ}F\), the boiling point of water.

FAQ

Why does -40 give the same number in C and F? The Celsius and Fahrenheit lines cross at -40, so -40 °C equals exactly -40 °F.

What is absolute zero? It is 0 K, which equals -273.15 °C and 0 °R (-459.67 °F). On the absolute scales (Kelvin and Rankine) a value below zero is physically impossible.

What is the Reaumur scale? An older scale where water freezes at 0 °Re and boils at 80 °Re, so each Reaumur degree spans 1.25 Celsius degrees.

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