MCP๋กœ ์—ฐ๊ฒฐ โ†’

๊ณ„์‚ฐ ์ž…๋ ฅ

๊ณต์‹

๊ณต์‹: ์˜จ๋„ ๋ณ€ํ™˜ ๊ณ„์‚ฐ๊ธฐ
Show calculation steps (1)
  1. Celsius to target

    Celsius to target: ์˜จ๋„ ๋ณ€ํ™˜ ๊ณ„์‚ฐ๊ธฐ

    Then convert Celsius to the target scale: F = Cx9/5+32, K = C+273.15, R = Cx9/5+491.67, Re = Cx4/5.

๊ด‘๊ณ 

๊ฒฐ๊ณผ

50 ยฐC =
122
ยฐF (Fahrenheit)
๋ณ€ํ™˜ ์ „ 50 ยฐC (Celsius)
์„ญ์”จ ๊ฒฝ์œ  50 ยฐC
๋ณ€ํ™˜ ํ›„ 122 ยฐF (Fahrenheit)

์ด ๊ณ„์‚ฐ๊ธฐ๋กœ ํ•  ์ˆ˜ ์žˆ๋Š” ๊ฒƒ

์ด ๋„๊ตฌ๋Š” ๋‹ค์„ฏ ๊ฐ€์ง€ ์˜จ๋„ ๋‹จ์œ„, ์ฆ‰ ์„ญ์”จ(ยฐC), ํ™”์”จ(ยฐF), ์ผˆ๋นˆ(K), ๋žญํ‚จ(ยฐR), ์—ด์”จ(ยฐRe) ๊ฐ€์šด๋ฐ ์–ด๋А ๋‘ ๋‹จ์œ„ ์‚ฌ์ด๋“  ์˜จ๋„ ๊ฐ’์„ ๋ณ€ํ™˜ํ•ด ์ค๋‹ˆ๋‹ค. ์ˆœ์ˆ˜ํ•œ ๋ฌผ๋ฆฌ ๋‹จ์œ„ ๋ณ€ํ™˜์ด๊ธฐ ๋•Œ๋ฌธ์— ์ง€์—ญ๋ณ„ ๊ทœ์น™์ด๋‚˜ ๊ฐ€์ •์ด ๋ผ์–ด๋“ค ์—ฌ์ง€๊ฐ€ ์—†์œผ๋ฉฐ, ์ „ ์„ธ๊ณ„ ์–ด๋””์„œ๋‚˜ ๊ฒฐ๊ณผ๊ฐ€ ๋™์ผํ•ฉ๋‹ˆ๋‹ค.

๋ฌผ์˜ ์–ด๋Š”์ ๊ณผ ๋“๋Š”์ ์„ ๊ธฐ์ค€์œผ๋กœ ์ •๋ ฌํ•œ ๋‹ค์„ฏ ๊ฐ€์ง€ ์˜จ๋„๊ณ„ ๋ˆˆ๊ธˆ
๋ฌผ์˜ ์–ด๋Š”์ ๊ณผ ๋“๋Š”์ ์—์„œ ๋น„๊ตํ•œ ๋‹ค์„ฏ ๊ฐ€์ง€ ์˜จ๋„ ์ฒ™๋„.

์‚ฌ์šฉ ๋ฐฉ๋ฒ•

๋ณ€ํ™˜ํ•  ์›๋ž˜ ๋‹จ์œ„๋ฅผ From(๋ณ€ํ™˜ ์ „)์—์„œ ๊ณ ๋ฅด๊ณ , ๋ฐ”๊พธ๊ณ  ์‹ถ์€ ๋‹จ์œ„๋ฅผ To(๋ณ€ํ™˜ ํ›„)์—์„œ ์„ ํƒํ•œ ๋’ค Value to Convert(๋ณ€ํ™˜ํ•  ๊ฐ’) ์นธ์— ์˜จ๋„๋ฅผ ์ž…๋ ฅํ•˜์„ธ์š”. ์Œ์ˆ˜๋„ ์ž…๋ ฅํ•  ์ˆ˜ ์žˆ์Šต๋‹ˆ๋‹ค(์˜ˆ: -40, ๋˜๋Š” ์˜ํ•˜์˜ ์„ญ์”จ ๊ฐ’). ๊ณ„์‚ฐ ๋ฒ„ํŠผ์„ ๋ˆ„๋ฅด๋ฉด ์ค‘๊ฐ„ ๋‹จ๊ณ„์ธ ์„ญ์”จ ๊ฐ’๊ณผ ํ•จ๊ป˜ ๊ฒฐ๊ณผ๊ฐ€ ํ‘œ์‹œ๋ฉ๋‹ˆ๋‹ค. From๊ณผ To์— ๊ฐ™์€ ๋‹จ์œ„๋ฅผ ์„ ํƒํ•˜๋ฉด ๊ฐ’์ด ๊ทธ๋Œ€๋กœ ๋ฐ˜ํ™˜๋ฉ๋‹ˆ๋‹ค.

๊ณต์‹ ์„ค๋ช…

์ด ๊ณ„์‚ฐ๊ธฐ๋Š” ์„ญ์”จ๋ฅผ ๊ธฐ์ค€์ (pivot)์œผ๋กœ ์‚ฌ์šฉํ•ฉ๋‹ˆ๋‹ค. 1๋‹จ๊ณ„๋Š” ์ž…๋ ฅ๊ฐ’์„ ์„ญ์”จ๋กœ ๋ฐ”๊ฟ‰๋‹ˆ๋‹ค. ํ™”์”จ์—์„œ๋Š” \(C = (F - 32) \times \tfrac{5}{9}\), ์ผˆ๋นˆ์—์„œ๋Š” \(C = K - 273.15\), ๋žญํ‚จ์—์„œ๋Š” \(C = (R - 491.67) \times \tfrac{5}{9}\), ์—ด์”จ์—์„œ๋Š” \(C = Re \times \tfrac{5}{4}\) ์ž…๋‹ˆ๋‹ค. 2๋‹จ๊ณ„๋Š” ๊ทธ ์„ญ์”จ ๊ฐ’์„ ๋ชฉํ‘œ ๋‹จ์œ„๋กœ ๋ณ€ํ™˜ํ•ฉ๋‹ˆ๋‹ค. \(F = C \times \tfrac{9}{5} + 32\), \(K = C + 273.15\), \(R = C \times \tfrac{9}{5} + 491.67\), \(Re = C \times \tfrac{4}{5}\) ์ž…๋‹ˆ๋‹ค. ์ •ํ™•ํ•œ ๋ถ„์ˆ˜(9/5, 5/9, 4/5, 5/4)๋ฅผ ์‚ฌ์šฉํ•ด ๋ฐ˜์˜ฌ๋ฆผ ์˜ค์ฐจ๊ฐ€ ์Œ“์ด๋Š” ๊ฒƒ์„ ๋ฐฉ์ง€ํ•ฉ๋‹ˆ๋‹ค. ์ด๋“ค ๋‹จ์œ„๋Š” ์˜์ ์ด ์„œ๋กœ ๋‹ค๋ฅด๊ธฐ ๋•Œ๋ฌธ์— ๊ณฑ์…ˆ๊ณผ ๋ง์…ˆ์ด ํ•จ๊ป˜ ๋“ค์–ด๊ฐ€๋Š” ์•„ํ•€(affine) ๋ณ€ํ™˜์ž…๋‹ˆ๋‹ค. ์ผˆ๋นˆ๊ณผ ๋žญํ‚จ์€ ์ ˆ๋Œ€ ์˜๋„์—์„œ ์‹œ์ž‘ํ•˜๊ณ , ์—ด์”จ๋Š” ๋ฌผ์˜ ์–ด๋Š”์ ์„ 0, ๋“๋Š”์ ์„ 80์œผ๋กœ ๋‘ก๋‹ˆ๋‹ค.

๊ธฐ์šธ๊ธฐ 5๋ถ„์˜ 9, ์ ˆํŽธ 32์ธ ์„ญ์”จ์™€ ํ™”์”จ์˜ ์„ ํ˜• ๊ด€๊ณ„
์„ญ์”จ์—์„œ ํ™”์”จ๋กœ์˜ ๋ณ€ํ™˜์€ ๊ธฐ์šธ๊ธฐ 9/5, ์ ˆํŽธ 32์ธ ์ง์„ ์ด๋‹ค.

์˜ˆ์ œ ํ’€์ด

50 ยฐC๋ฅผ ยฐF๋กœ ๋ณ€ํ™˜ํ•ด ๋ด…์‹œ๋‹ค. 1๋‹จ๊ณ„: ์ž…๋ ฅ๊ฐ’์ด ์ด๋ฏธ ์„ญ์”จ์ด๋ฏ€๋กœ \(C = 50\) ์ž…๋‹ˆ๋‹ค. 2๋‹จ๊ณ„: $$^{\circ}F = 50 \times \tfrac{9}{5} + 32 = 90 + 32 = 122$$ ๋”ฐ๋ผ์„œ 50 ยฐC๋Š” 122 ยฐF๊ฐ€ ๋ฉ๋‹ˆ๋‹ค. ๋˜ ๋‹ค๋ฅธ ๊ฒ€์‚ฐ์œผ๋กœ, 80 ยฐRe๋Š” \(C = 80 \times \tfrac{5}{4} = 100\) ยฐC๋กœ ๋ณ€ํ™˜๋˜๊ณ , ์ด๋Š” ๋‹ค์‹œ \(100 \times \tfrac{9}{5} + 32 = 212\) ยฐF, ๊ณง ๋ฌผ์˜ ๋“๋Š”์ ์ด ๋ฉ๋‹ˆ๋‹ค.

์ž์ฃผ ๋ฌป๋Š” ์งˆ๋ฌธ

์™œ -40์€ ์„ญ์”จ์™€ ํ™”์”จ์—์„œ ๊ฐ™์€ ์ˆซ์ž๊ฐ€ ๋˜๋‚˜์š”? ์„ญ์”จ์™€ ํ™”์”จ์˜ ๊ทธ๋ž˜ํ”„ ์ง์„ ์ด -40์—์„œ ๋งŒ๋‚˜๊ธฐ ๋•Œ๋ฌธ์—, -40 ยฐC๋Š” ์ •ํ™•ํžˆ -40 ยฐF์™€ ๊ฐ™์Šต๋‹ˆ๋‹ค.

์ ˆ๋Œ€ ์˜๋„๋ž€ ๋ฌด์—‡์ธ๊ฐ€์š”? ์ ˆ๋Œ€ ์˜๋„๋Š” 0 K์ด๋ฉฐ, ์ด๋Š” -273.15 ยฐC, 0 ยฐR(-459.67 ยฐF)์— ํ•ด๋‹นํ•ฉ๋‹ˆ๋‹ค. ์ผˆ๋นˆ๊ณผ ๋žญํ‚จ ๊ฐ™์€ ์ ˆ๋Œ€ ์˜จ๋„ ์ฒ™๋„์—์„œ๋Š” 0๋ณด๋‹ค ๋‚ฎ์€ ๊ฐ’์ด ๋ฌผ๋ฆฌ์ ์œผ๋กœ ์กด์žฌํ•  ์ˆ˜ ์—†์Šต๋‹ˆ๋‹ค.

์—ด์”จ(Reaumur) ์ฒ™๋„๋Š” ๋ฌด์—‡์ธ๊ฐ€์š”? ๋ฌผ์ด 0 ยฐRe์—์„œ ์–ผ๊ณ  80 ยฐRe์—์„œ ๋“๋Š” ์˜› ์˜จ๋„ ์ฒ™๋„๋กœ, 1 ์—ด์”จ๋„๋Š” ์„ญ์”จ 1.25๋„์— ํ•ด๋‹นํ•ฉ๋‹ˆ๋‹ค.

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