Connect via MCP →

Enter Calculation

Formula

Advertisement

Results

Power Dissipated
40
watts (W)
Current (I) 2 A
Resistance (R) 10 Ω
Formula P = I² × R

What Is Power Dissipation?

Power dissipation is the rate at which electrical energy is converted into heat as current flows through a resistive component. When current passes through a resistor, the resistor opposes that flow and the lost energy appears as heat. This calculator uses the classic relationship \(P = I^2 \times R\) to find the power dissipated, where P is power in watts, I is current in amperes, and R is resistance in ohms. It applies universally to any resistive circuit element.

Resistor in a circuit with current flowing through it releasing heat
Power dissipation: current through a resistor is converted into heat.

How to Use This Calculator

Enter the current flowing through the component in amperes (A) and its resistance in ohms (Ω). The calculator squares the current, multiplies it by the resistance, and returns the dissipated power in watts (W). Use this to size resistors, predict heat output, choose heat sinks, or verify that a component stays within its power rating.

The Formula Explained

The equation \(P = I^2 R\) comes from combining Ohm's law (\(V = IR\)) with the general power formula (\(P = VI\)). Substituting \(V = IR\) into \(P = VI\) gives $$P = (IR) \cdot I = I^2 R.$$ Because current is squared, doubling the current quadruples the power dissipated — a key reason high-current connections must be sized carefully.

Diagram showing the relationship P equals I squared times R
Power equals current squared multiplied by resistance.

Worked Example

Suppose a current of 2 A flows through a 10 Ω resistor. Then $$P = (2)^2 \times 10 = 4 \times 10 = 40 \text{ watts}.$$ That resistor would need a power rating comfortably above 40 W to avoid overheating.

FAQ

Can I use \(P = I^2 R\) for AC circuits? Yes, for resistive (real-power) dissipation use the RMS current value as I.

What if I only know voltage and resistance? Use the equivalent form \(P = V^2/R\) instead, since both derive from Ohm's law.

Why is the current squared? Power depends on both the current and the voltage drop (which itself is proportional to current), so it scales with the square of the current.

Last updated: