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Skin Depth (δ)
65.1924
micrometers (µm)
Skin depth (mm) 0.065192 mm
Skin depth (m) 0.000065192 m
Resistivity ρ (Ω·m) 0.00000001678

What is skin depth?

Skin depth (\(\delta\)) describes how deeply an alternating current penetrates into a conductor. Because of the skin effect, AC current concentrates near the conductor's surface, with current density falling off exponentially with depth. The skin depth is the distance at which the current density has dropped to about 37% (\(1/e\)) of its surface value. This calculator works for any conductor and any frequency — it is a universal physics tool.

Cross-section of a cylindrical wire showing AC current concentrated near the surface
Skin effect: AC current crowds near the conductor's surface, leaving the core nearly unused.

How to use this calculator

Enter the operating frequency in hertz, the conductor's conductivity \(\sigma\) in siemens per meter, and its relative permeability \(\mu_r\). For most non-magnetic metals such as copper, aluminum and gold, \(\mu_r \approx 1\). For ferromagnetic materials like iron or steel, \(\mu_r\) can be in the hundreds or thousands. The result is reported in micrometers, millimeters and meters, plus the resistivity \(\rho = 1/\sigma\).

The formula explained

The skin depth is $$\delta = \dfrac{1}{\sqrt{\pi \, f \cdot \mu \cdot \sigma}},$$ which is mathematically equivalent to \(\delta = \sqrt{2\rho / (\omega \cdot \mu)}\) where \(\omega = 2\pi f\) and \(\rho = 1/\sigma\). Here \(\mu = \mu_0 \cdot \mu_r\) and \(\mu_0 = 4\pi\times10^{-7}\ \text{H/m}\) is the permeability of free space. Higher frequency, conductivity or permeability all reduce the skin depth.

Graph of current density decaying exponentially with depth into a conductor
Current density falls off exponentially with depth, dropping to about 37% at one skin depth.

Worked example

For copper at 1 MHz with \(\sigma = 5.96\times10^{7}\ \text{S/m}\) and \(\mu_r = 1\): \(\mu = 4\pi\times10^{-7} \approx 1.2566\times10^{-6}\ \text{H/m}\). Then $$\pi \cdot f \cdot \mu \cdot \sigma = 3.1416 \times 10^{6} \times 1.2566\times10^{-6} \times 5.96\times10^{7} \approx 2.3527\times10^{8}.$$ $$\delta = \frac{1}{\sqrt{2.3527\times10^{8}}} \approx 6.519\times10^{-5}\ \text{m} = 65.19\ \mu\text{m}.$$

FAQ

Why does current avoid the center of a wire? Eddy currents induced by the changing magnetic field oppose the flow in the core, pushing current outward toward the surface.

Does skin depth increase or decrease with frequency? It decreases as frequency rises — at very high frequencies current flows in an extremely thin surface layer, which is why high-frequency conductors are often silver-plated or hollow.

What conductivity should I use for copper? Annealed copper is about \(5.8\text{–}5.96\times10^{7}\ \text{S/m}\) at room temperature; this example uses \(5.96\times10^{7}\ \text{S/m}\).

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