MCP๋กœ ์—ฐ๊ฒฐ โ†’

๊ณ„์‚ฐ ์ž…๋ ฅ

๊ณต์‹

๊ด‘๊ณ 

๊ฒฐ๊ณผ

ํ•™๊ธฐ GPA
3.51
ํ•™์  ๊ฐ€์ค‘, 4.0 ๋งŒ์ 
๋ฐ˜์˜๋œ ๊ณผ๋ชฉ ์ˆ˜ 3
์ „์ฒด ํ•™์  10
์ด ์„ฑ์  ํฌ์ธํŠธ 35.1

ํ•™๊ธฐ GPA๋ž€?

ํ•™๊ธฐ GPA๋Š” ํ•œ ํ•™๊ธฐ ๋™์•ˆ ์ˆ˜๊ฐ•ํ•œ ๋ชจ๋“  ๊ณผ๋ชฉ์—์„œ ์–ผ๋งˆ๋‚˜ ์ž˜ํ–ˆ๋Š”์ง€๋ฅผ ํ•œ ์ˆซ์ž๋กœ ๋ณด์—ฌ์ฃผ๋Š” ์ง€ํ‘œ์ž…๋‹ˆ๋‹ค. ๋‹จ์ˆœํžˆ ์„ฑ์ ์„ ํ‰๊ท  ๋‚ด๋Š” ๊ฒƒ๊ณผ ๋‹ฌ๋ฆฌ, GPA๋Š” ํ•™์ (credit) ๊ฐ€์ค‘ ํ‰๊ท ์œผ๋กœ ๊ณ„์‚ฐ๋ฉ๋‹ˆ๋‹ค. ์ฆ‰, 4ํ•™์ ์งœ๋ฆฌ ๊ณผ๋ชฉ์ด 1ํ•™์ ์งœ๋ฆฌ ๊ณผ๋ชฉ๋ณด๋‹ค GPA์— ๋” ํฐ ์˜ํ–ฅ์„ ๋ฏธ์นฉ๋‹ˆ๋‹ค. ์ด ๊ณ„์‚ฐ๊ธฐ๋Š” ๋ฏธ๊ตญ์—์„œ ๋„๋ฆฌ ์“ฐ์ด๋Š” 4.0 ๋งŒ์  ์ฒ™๋„๋ฅผ ์‚ฌ์šฉํ•ฉ๋‹ˆ๋‹ค. A = 4.0, B = 3.0, C = 2.0, D = 1.0, F = 0.0์ด๋ฉฐ, A- = 3.7์ด๋‚˜ B+ = 3.3์ฒ˜๋Ÿผ +/- ๋‹จ๊ณ„๋„ ๋ฐ˜์˜ํ•ฉ๋‹ˆ๋‹ค. (ํ•œ๊ตญ ๋Œ€ํ•™์€ 4.5 ๋งŒ์ ์„ ์“ฐ๋Š” ๊ณณ์ด ๋งŽ์œผ๋‹ˆ, ํ•™๊ต ๊ธฐ์ค€์ด 4.0์ธ์ง€ 4.5์ธ์ง€ ๋จผ์ € ํ™•์ธํ•˜์„ธ์š”.)

์‚ฌ์šฉ ๋ฐฉ๋ฒ•

์ด๋ฒˆ ํ•™๊ธฐ์— ๋“ค์€ ๊ณผ๋ชฉ๋งˆ๋‹ค ํ‰์ (grade points)๊ณผ ํ•™์ (credit hours)์„ ์ž…๋ ฅํ•˜์„ธ์š”. ํ‰์ ์€ ๋ฐ›์€ ์„ฑ์ ์„ 4.0 ์ฒ™๋„์˜ ์ˆซ์ž๋กœ ํ™˜์‚ฐํ•œ ๊ฐ’์ด๊ณ , ํ•™์ ์€ ๊ทธ ๊ณผ๋ชฉ์˜ ์ด์ˆ˜ ํ•™์ ์ž…๋‹ˆ๋‹ค. ์‚ฌ์šฉํ•˜์ง€ ์•Š๋Š” ์นธ์€ ๋น„์›Œ ๋‘๋ฉด ๋ฉ๋‹ˆ๋‹ค. ๊ณ„์‚ฐ๊ธฐ๋Š” ๊ณผ๋ชฉ๋ณ„๋กœ ํ‰์ ๊ณผ ํ•™์ ์„ ๊ณฑํ•œ ๋’ค ๋ชจ๋‘ ๋”ํ•˜๊ณ , ์ด๋ฅผ ์ „์ฒด ํ•™์ ์œผ๋กœ ๋‚˜๋ˆ„์–ด GPA๋ฅผ ์‚ฐ์ถœํ•ฉ๋‹ˆ๋‹ค.

๊ณ„์‚ฐ ๊ณต์‹

๊ณต์‹์€ ๋‹ค์Œ๊ณผ ๊ฐ™์Šต๋‹ˆ๋‹ค.

$$\text{GPA} = \dfrac{\sum (\text{ํ‰์ } \times \text{ํ•™์ })}{\sum \text{ํ•™์ }}$$

๋ถ„์ž๋Š” ์ด๋ฒˆ ํ•™๊ธฐ์— ์Œ“์€ ์ด "์„ฑ์  ํฌ์ธํŠธ(quality points)"์ด๊ณ , ๋ถ„๋ชจ๋Š” ์‹ ์ฒญํ•œ ์ „์ฒด ํ•™์ ์ž…๋‹ˆ๋‹ค. ๊ณผ๋ชฉ๋ณ„ ์„ฑ์  ํฌ์ธํŠธ๋Š” \(QP_i = g_i \times c_i\)๋กœ ๊ตฌํ•ฉ๋‹ˆ๋‹ค. ๋‘˜์„ ๋‚˜๋ˆ„๋ฉด ๊ฐ ๊ณผ๋ชฉ์˜ ๋น„์ค‘์„ ๋ฐ˜์˜ํ•œ ๊ฐ€์ค‘ ํ‰๊ท ์ด ๋‚˜์˜ต๋‹ˆ๋‹ค.

ํ‰์ ร—ํ•™์ ์„ ํ•ฉ์‚ฐํ•ด ์ด ํ•™์ ์œผ๋กœ ๋‚˜๋ˆ„๋Š” ๋„ํ‘œ
๊ฐ ๊ณผ๋ชฉ์˜ ํ‰์ ์— ํ•™์ ์„ ๊ณฑํ•ด ํ•ฉ์‚ฐํ•œ ๋’ค ์ด ํ•™์ ์œผ๋กœ ๋‚˜๋ˆ•๋‹ˆ๋‹ค.

์˜ˆ์‹œ๋กœ ๋ณด๊ธฐ

์„ธ ๊ณผ๋ชฉ์„ ๋“ค์—ˆ๋‹ค๊ณ  ๊ฐ€์ •ํ•ด ๋ด…์‹œ๋‹ค. A(4.0) 3ํ•™์ , B(3.0) 4ํ•™์ , A-(3.7) 3ํ•™์ ์ž…๋‹ˆ๋‹ค. ์„ฑ์  ํฌ์ธํŠธ๋Š” ๋‹ค์Œ๊ณผ ๊ฐ™์ด ๊ณ„์‚ฐ๋ฉ๋‹ˆ๋‹ค.

$$(4.0 \times 3) + (3.0 \times 4) + (3.7 \times 3) = 12 + 12 + 11.1 = 35.1$$

์ „์ฒด ํ•™์  = \(3 + 4 + 3 = 10\). ๋”ฐ๋ผ์„œ

$$\text{GPA} = \dfrac{35.1}{10} = \mathbf{3.51}$$

์ด ๋ฉ๋‹ˆ๋‹ค.

์„ธ ๊ณผ๋ชฉ์„ ํ•˜๋‚˜์˜ ํ‰์ ์œผ๋กœ ํ•ฉ์น˜๋Š” ์˜ˆ์‹œ ํ‘œ
์‹ค์ œ ์˜ˆ์‹œ: ์„ฑ์ ๊ณผ ํ•™์ ์„ ํ•ฉ์ณ ํ•™๊ธฐ ์ตœ์ข… ํ‰์ ์„ ๊ณ„์‚ฐํ•ฉ๋‹ˆ๋‹ค.

์ž์ฃผ ๋ฌป๋Š” ์งˆ๋ฌธ

ํ‰์ ์—๋Š” ์–ด๋–ค ์ˆซ์ž๋ฅผ ๋„ฃ์–ด์•ผ ํ•˜๋‚˜์š”? ๋ณธ์ธ ํ•™๊ต์˜ 4.0 ์ฒ™๋„ ๊ฐ’์„ ์‚ฌ์šฉํ•˜์„ธ์š”. A=4.0, A-=3.7, B+=3.3, B=3.0, B-=2.7, C+=2.3, C=2.0 ๋“ฑ์œผ๋กœ ์ž…๋ ฅํ•˜๋ฉด ๋ฉ๋‹ˆ๋‹ค.

์™œ GPA๋Š” ํ•™์  ๊ฐ€์ค‘ ํ‰๊ท ์ธ๊ฐ€์š”? ํ•™์ ์ด ๋งŽ์€ ๊ณผ๋ชฉ์—์„œ ๋ฐ›์€ ์ข‹์€ ์„ฑ์ ์ด, ํ•™์ ์ด ์ ์€ ๊ณผ๋ชฉ์˜ ๊ฐ™์€ ์„ฑ์ ๋ณด๋‹ค ๋” ๋งŽ์ด ๋ฐ˜์˜๋˜์–ด์•ผ ํ•˜๊ธฐ ๋•Œ๋ฌธ์ž…๋‹ˆ๋‹ค. ํ•™์ ์œผ๋กœ ๊ฐ€์ค‘ํ•˜๋ฉด ๊ฐ ๊ณผ๋ชฉ์˜ ํ•™์Šต๋Ÿ‰์ด ์ž์—ฐ์Šค๋Ÿฝ๊ฒŒ ๋ฐ˜์˜๋ฉ๋‹ˆ๋‹ค.

์ด ๊ณ„์‚ฐ๊ธฐ๋กœ ์ „์ฒด ๋ˆ„์  ํ‰์ (๋ˆ„๊ณ„ GPA)๋„ ์•Œ ์ˆ˜ ์žˆ๋‚˜์š”? ์•„๋‹ˆ์š”. ์ด ๋„๊ตฌ๋Š” ํ•œ ํ•™๊ธฐ์˜ GPA๋งŒ ๊ณ„์‚ฐํ•ฉ๋‹ˆ๋‹ค. ๋ˆ„์  GPA๋ฅผ ๊ตฌํ•˜๋ ค๋ฉด ๋ชจ๋“  ํ•™๊ธฐ์˜ ์„ฑ์  ํฌ์ธํŠธ์™€ ํ•™์ ์„ ์ „๋ถ€ ํ•ฉ์‚ฐํ•ด์„œ ๊ณ„์‚ฐํ•ด์•ผ ํ•ฉ๋‹ˆ๋‹ค.

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