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Volumetric Flow Rate (Q)
0.006284
m³/s
Flow rate 6.284 L/s
Throat velocity 3.201 m/s
Inlet area A₁ 0.007854 m²
Throat area A₂ 0.001963 m²

What is the Venturi Flow Rate Calculator?

A Venturi meter measures the volumetric flow rate of a fluid through a pipe by exploiting Bernoulli's principle: as fluid accelerates through a narrowed throat, its pressure drops. By measuring that pressure difference between the inlet and the throat, you can compute the flow rate. This universal calculator works for any incompressible fluid in any consistent SI unit set.

Cross-section of a Venturi tube showing wide inlet narrowing to a throat then widening again, with pressure readings
A Venturi meter narrows the flow at the throat, where velocity rises and pressure drops.

How to use it

Enter the inlet diameter \(D_1\) and throat diameter \(D_2\) (in metres), the measured pressure difference \(\Delta P\) (in pascals), the fluid density \(\rho\) (in kg/m³), and the discharge coefficient \(C_d\) (typically 0.95–0.99 for a well-made Venturi). The calculator returns the volumetric flow rate in m³/s and L/s, the throat velocity, and both cross-sectional areas.

The formula explained

The governing equation is:

$$Q = \text{C}_d \cdot A_2 \cdot \sqrt{\dfrac{2\,\Delta P}{\rho\left(1 - \left(\frac{A_2}{A_1}\right)^2\right)}}$$

where \(A_1 = \frac{\pi}{4}\text{D}_1^{2}\) and \(A_2 = \frac{\pi}{4}\text{D}_2^{2}\) are the inlet and throat areas. The discharge coefficient \(C_d\) corrects for real-world friction and non-ideal flow. The throat velocity is simply \(v_2 = Q/A_2\).

Annotated diagram mapping formula symbols to the Venturi geometry
Each symbol in the equation maps to a part of the Venturi: areas A1 and A2, pressure drop ΔP and density ρ.

Worked example

For \(D_1 = 0.1\) m, \(D_2 = 0.05\) m, \(\Delta P = 5000\) Pa, \(\rho = 1000\) kg/m³ and \(C_d = 1\): \(A_1 = 0.0078540\) m², \(A_2 = 0.0019635\) m², area ratio \(= 0.25\), so \(1 - 0.25^2 = 0.9375\). Then $$Q = 1 \times 0.0019635 \times \sqrt{\frac{10000}{937.5}} = 1 \times 0.0019635 \times 3.2660 = 0.006413 \text{ m}^3/\text{s},$$ and throat velocity \(= 0.006413 / 0.0019635 \approx 3.266\) m/s. With \(C_d = 0.98\), velocity scales to about 3.20 m/s.

FAQ

What value should I use for \(C_d\)? A classical Venturi tube typically has a discharge coefficient between 0.95 and 0.99. Use 1.0 for an idealized theoretical calculation.

Does this work for gases? The equation assumes an incompressible fluid, so it is accurate for liquids and for gases at low velocity/low pressure-drop. For compressible flow you need an expansibility factor.

Why is the throat velocity higher than the inlet velocity? Conservation of mass (continuity) forces the fluid to speed up through the smaller throat area, which is exactly why the pressure drops there.

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