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Work Done
50
joules (J)
Force 10 N
Distance 5 m
Angle θ

What Is the Work Calculator?

This calculator finds the mechanical work done when a constant force acts over a distance. In physics, work is the transfer of energy that occurs when a force moves an object. The result is expressed in joules (J), where one joule equals one newton-metre.

How to Use It

Enter the magnitude of the applied force in newtons (N), the distance the object moves in metres (m), and the angle θ in degrees between the force vector and the direction of motion. Click calculate to get the work done. If the force is in the same direction as motion, use \(\theta = 0°\).

The Formula Explained

The work equation is $$W = F \cdot d \cdot \cos(\theta)$$ Only the component of the force along the direction of motion does work, which is why we multiply by \(\cos(\theta)\). When \(\theta = 0°\), \(\cos(\theta) = 1\) and all of the force contributes. When \(\theta = 90°\), \(\cos(\theta) = 0\) and no work is done — this is why carrying a bag horizontally while it pushes down on you does no work. When \(\theta\) is between 90° and 180°, work becomes negative, meaning the force removes energy.

Three scenarios showing positive, zero, and negative work based on the angle between force and motion.
Positive, zero, and negative work for angles of 0°, 90°, and 180°.
Diagram showing a force vector applied at an angle to the direction of motion, with the horizontal component projected onto the displacement.
Work depends on the force component along the displacement: \(F\cdot\cos(\theta)\).

Worked Example

Suppose you push a box with a force of 20 N over a distance of 10 m at an angle of 60°. Then $$W = 20 \times 10 \times \cos(60°) = 20 \times 10 \times 0.5 = 100 \text{ J}$$

FAQ

What units does the result use? Joules (J), assuming force in newtons and distance in metres.

Can work be negative? Yes. If the angle exceeds 90°, the force opposes the motion and work is negative, indicating energy is taken away from the object.

Why include the cosine term? Force is a vector. Only its component aligned with the displacement performs work, captured by \(\cos(\theta)\).

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