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Current Through R1
0.6667
amperes (A)
Current through R1 0.6667 A
Current through R2 0.3333 A

What Is a Current Divider?

A current divider is a simple parallel circuit in which a total current splits between two (or more) branches. Because both resistors share the same voltage, the current through each branch is inversely proportional to its resistance — the smaller resistor carries the larger current. This calculator handles the common two-resistor case using Kirchhoff's current law and Ohm's law.

Schematic of a current source feeding two parallel resistors R1 and R2 with branch currents labeled
A current divider: the total current splits between two parallel resistors R1 and R2.

How to Use It

Enter the total current entering the parallel combination (in amperes), then enter the two resistor values R1 and R2 (in ohms). The calculator returns the current flowing through each resistor. The two branch currents always add up to the total current you entered.

The Formula Explained

For two resistors in parallel, the current through R1 is:

$$I_{R1} = \text{I}_{\text{total}} \cdot \frac{\text{R2}}{\text{R1} + \text{R2}}$$

Notice the resistor in the numerator is the other branch's resistance. This is because more current naturally flows down the path of least resistance, so R1 receives a share weighted by R2. The current through R2 follows the same rule with R1 in the numerator.

Diagram showing the inverse-proportion rule: smaller resistor carries larger current
More current flows through the smaller resistor — the branch current is inversely proportional to its resistance.

Worked Example

Suppose 1 A enters a node and splits between R1 = 100 Ω and R2 = 200 Ω. Then:

$$I_{R1} = 1 \times \frac{200}{100 + 200} = \frac{200}{300} = 0.6667 \text{ A}$$$$I_{R2} = 1 \times \frac{100}{300} = 0.3333 \text{ A}$$

The currents sum to 1 A, confirming Kirchhoff's current law, and the smaller resistor (R1) carries the larger current.

FAQ

Why does the smaller resistor get more current? Both resistors have the same voltage across them. By Ohm's law (\(I = V/R\)), a smaller R means a larger I.

Does this work for more than two resistors? This tool covers the two-resistor case. For more branches, replace the "other" resistance with the parallel combination of all the remaining branches.

What units should I use? Use amperes for current and ohms for resistance. The result is in amperes. The ratio is unitless, so consistent units are all that matter.

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