Connect via MCP →

Enter Calculation

Formula

Advertisement

Results

Number Density
334.2848E20
particles per cm³
Mass density ρ 1 g/cm³
Molar mass M 18.015 g/mol
Avogadro's number 6.02214076 × 10²³ /mol

What Is Number Density?

Number density is the number of particles (atoms, molecules, or ions) contained in a unit volume of a substance. It is a fundamental quantity in physics, chemistry, and materials science, used in kinetic theory, diffusion, plasma physics, and semiconductor doping. This calculator returns the number density in particles per cubic centimeter from a substance's mass density and molar mass.

A fixed cubic volume containing scattered identical particles, illustrating particles per unit volume
Number density measures how many particles occupy a unit volume.

How to Use This Calculator

Enter the mass density ρ of the material in grams per cubic centimeter (g/cm³) and its molar mass M in grams per mole (g/mol). The tool multiplies the density by Avogadro's number and divides by the molar mass to obtain the number of particles per cm³.

The Formula Explained

The relationship is $$n = \frac{\rho \cdot N_A}{M}$$, where \(\rho\) is mass density, \(N_A = 6.02214076 \times 10^{23}\ /\text{mol}\) is Avogadro's number, and \(M\) is molar mass. Mass density (g/cm³) divided by molar mass (g/mol) gives moles per cm³; multiplying by \(N_A\) converts moles to individual particles.

Diagram showing density times Avogadro number divided by molar mass equals number density
The formula combines mass density, Avogadro's number, and molar mass.

Worked Example

Water has a density of about 1 g/cm³ and a molar mass of 18.015 g/mol. Then $$n = \frac{1 \times 6.02214076 \times 10^{23}}{18.015} \approx 3.343 \times 10^{22}\ \text{molecules per cm}^3.$$ So roughly 33 sextillion water molecules occupy each cubic centimeter.

FAQ

What units does the result use? Particles per cubic centimeter (cm⁻³). Multiply by 10⁶ to convert to particles per cubic meter.

Does it work for elements? Yes — use the element's mass density and its atomic (molar) mass; the result is atoms per cm³.

What is Avogadro's number? The number of entities in one mole, exactly 6.02214076 × 10²³ since the 2019 SI redefinition.

Last updated: