Connect via MCP →

Enter Calculation

Formula

Advertisement

Results

Acceleration
175,850,713,501.647
m/s²
Electric force (F = qE) 0 N

What It Calculates

This calculator finds the acceleration experienced by a charged particle placed in a uniform electric field. When a charge sits in an electric field, the field exerts a force on it, and by Newton's second law that force produces an acceleration. The relationship combines electrostatics and mechanics into one compact formula: \(a = qE/m\).

Charged particle accelerating between two charged plates in a uniform electric field
A positive charge \(q\) experiences a force in the field \(E\), producing acceleration \(a\).

How to Use It

Enter three values: the particle's electric charge \(q\) in coulombs (C), the electric field strength \(E\) in newtons per coulomb (N/C), and the particle's mass \(m\) in kilograms (kg). The calculator multiplies the charge by the field to get the electric force (\(F = qE\)), then divides by the mass to give the acceleration in meters per second squared (m/s²). For subatomic particles such as electrons or protons, use scientific values like \(1.602\times10^{-19}\) C for charge.

The Formula Explained

The electric force on a charge is \(F = qE\). Newton's second law states \(F = ma\), so \(a = F/m\). Substituting the electric force gives $$a = \dfrac{qE}{m}$$ A larger charge or stronger field increases acceleration, while a larger mass decreases it. The direction of acceleration follows the field for a positive charge and opposes it for a negative charge.

Advertisement
Force diagram relating electric force, field and charge to acceleration
The field exerts force \(F = qE\), and Newton's second law gives \(a = qE/m\).

Worked Example

An electron (\(q = 1.602\times10^{-19}\) C, \(m = 9.11\times10^{-31}\) kg) is placed in a field of 1000 N/C. The force is $$F = (1.602\times10^{-19})(1000) = 1.602\times10^{-16}\ \text{N}$$ The acceleration is $$a = \dfrac{1.602\times10^{-16}}{9.11\times10^{-31}} \approx 1.759\times10^{14}\ \text{m/s}^2$$ — an enormous value because the electron's mass is tiny.

Constants & Reference Values

The acceleration of a charged particle in a uniform electric field follows from Newton's second law combined with the electric force, \(a = \frac{qE}{m}\). To use this relation you need the particle's charge \(q\) (in coulombs, C), the field strength \(E\) (in newtons per coulomb, N/C, equivalently volts per metre, V/m), and the mass \(m\) (in kilograms, kg). The table below lists commonly used reference values.

Quantity Symbol Value Unit
Elementary charge \(e\) \(1.602\times10^{-19}\) C
Electron charge \(q_e\) \(-1.602\times10^{-19}\) C
Electron mass \(m_e\) \(9.11\times10^{-31}\) kg
Proton charge \(q_p\) \(+1.602\times10^{-19}\) C
Proton mass \(m_p\) \(1.673\times10^{-27}\) kg
Alpha particle charge \(q_\alpha\) \(+3.204\times10^{-19}\) (\(=2e\)) C
Alpha particle mass \(m_\alpha\) \(6.645\times10^{-27}\) kg
Charge-to-mass ratio (electron) \(e/m_e\) \(1.759\times10^{11}\) C/kg
Charge-to-mass ratio (proton) \(e/m_p\) \(9.58\times10^{7}\) C/kg

Note that the electric field unit N/C is dimensionally identical to V/m, so a field expressed either way can be entered directly. The sign of the charge sets the direction of the acceleration relative to the field: positive charges accelerate along \(\vec{E}\), negative charges opposite to it.

Advertisement

Key Terms Defined

Charge (\(q\), coulombs, C)
The electric charge carried by the particle. It can be positive or negative, and its magnitude is often expressed as a multiple of the elementary charge \(e = 1.602\times10^{-19}\) C. The sign determines whether the particle accelerates with or against the field.
Electric field strength (\(E\), N/C or V/m)
The force per unit charge exerted by the field at a point, \(E = F/q\). Newtons per coulomb (N/C) and volts per metre (V/m) are equivalent units. A field points from regions of high to low potential.
Mass (\(m\), kilograms, kg)
The inertial mass of the particle, which resists acceleration. Larger mass yields smaller acceleration for the same force, since \(a \propto 1/m\).
Acceleration (\(a\), metres per second squared, m/s²)
The rate of change of the particle's velocity, given by \(a = qE/m\). It is directed along the electric force.
Electric force (\(F\), newtons, N)
The force the field exerts on the charge, \(F = qE\). Combined with Newton's second law \(F = ma\), this yields the acceleration relation \(a = qE/m\).

FAQ

Does the charge sign matter? The magnitude of acceleration is the same; the sign tells you the direction relative to the field. Enter the signed charge if you want a signed result.

What units should I use? SI units: coulombs, N/C, and kilograms give acceleration in m/s².

Is gravity included? No. This computes only the electric-field acceleration. For charged particles in everyday fields the electric acceleration usually dwarfs gravity.

Last updated: