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Rate Constant k
0.713219
in units of A (e.g. 1/s)
R · T (J/mol) 2,477.57
Exponent −Ea/(R·T) -30.271572

What is the Rate Constant Calculator?

This tool computes the reaction rate constant k using the Arrhenius equation, one of the cornerstones of chemical kinetics. Given the pre-exponential factor (frequency factor) A, the activation energy Ea, and the absolute temperature T, it returns k in the same units as A. It is universal physical chemistry — no country or jurisdiction applies.

How to use it

Enter the pre-exponential factor A (often around 1013 1/s for simple unimolecular reactions), the activation energy Ea in joules per mole, and the temperature in kelvin. The calculator uses the gas constant R = 8.314 J/(mol·K). Make sure your activation energy is in J/mol, not kJ/mol — multiply kJ/mol values by 1000 first.

The formula explained

The Arrhenius equation is $$k = A \cdot e^{-E_a / (R \cdot T)}$$ The exponential term is the Boltzmann factor: it gives the fraction of molecular collisions with enough energy to react. As temperature rises, the exponent becomes less negative, so k grows rapidly. Higher activation energy makes the exponent more negative, slowing the reaction.

Curve showing rate constant increasing exponentially with temperature
The rate constant k rises sharply as temperature T increases.
Energy profile curve showing the activation energy barrier between reactants and products
Activation energy Ea is the barrier height that the temperature term in the Arrhenius equation must overcome.

Worked example

With \(A = 1\times10^{13}\) 1/s, \(E_a = 75{,}000\) J/mol, and \(T = 298\) K: $$R \cdot T = 8.314 \times 298 = 2477.572 \text{ J/mol}$$ The exponent is $$\frac{-75000}{2477.572} = -30.272$$ Then $$k = 10^{13} \times e^{-30.272} \approx 10^{13} \times 7.13\times10^{-14} \approx 0.713 \text{ 1/s}$$

FAQ

What units does k have? The same as A. For first-order reactions A and k are in 1/s; for second-order reactions they are in L/(mol·s).

Should Ea be in kJ or J? This calculator expects J/mol. Convert kJ/mol to J/mol by multiplying by 1000.

Why does a small temperature change matter so much? Because temperature appears inside an exponential, even a modest rise can multiply the rate constant several-fold — a rule of thumb is that rates roughly double for every 10 K increase.

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