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  1. Moment of Inertia I

    Moment of Inertia I: Section Modulus of a Rectangular Beam Calculator

    Second moment of area of the rectangular section

  2. Cross-Sectional Area

    Cross-Sectional Area: Section Modulus of a Rectangular Beam Calculator

    Area of the rectangular section

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Results

Section Modulus (S)
83,333.33
units³ (e.g. mm³)
Moment of Inertia (I) 4,166,666.67 units⁴
Cross-sectional Area 5,000 units²

What Is the Section Modulus?

The elastic section modulus (S) is a geometric property of a cross-section that measures its resistance to bending. For a solid rectangular beam of width b and height h, the section modulus about the centroidal axis is \(S = b \cdot h^{2} / 6\). A larger section modulus means a stiffer, stronger beam in bending. This is a universal geometry/mechanics tool — the result is expressed in cubic length units (e.g. mm³, cm³, in³) depending on the units you enter.

Rectangular beam cross-section with width b and height h, neutral axis through the centroid
A rectangular cross-section showing width b, height h, and the horizontal neutral axis through the centroid.

How to Use This Calculator

Enter the width b (the dimension parallel to the neutral axis) and the height h (the dimension in the direction of bending, measured perpendicular to the axis). The calculator returns the section modulus S, the moment of inertia \(I = b \cdot h^{3} / 12\), and the cross-sectional area. Keep your units consistent: if you enter millimetres, S comes out in mm³ and I in mm⁴.

The Formula Explained

Bending stress relates to the section modulus by \(\sigma = M / S\), where M is the applied bending moment. Section modulus is derived from the moment of inertia divided by the distance to the extreme fibre: \(S = I / c\). For a rectangle, \(I = b \cdot h^{3} / 12\) and \(c = h/2\), so $$S = \frac{b \cdot h^{3} / 12}{h/2} = \frac{b \cdot h^{2}}{6}.$$ Because height appears squared, increasing the depth of a beam is far more effective at boosting strength than increasing its width.

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Bending stress distribution across a rectangular beam height, linear from zero at neutral axis to maximum at outer fibers
Bending stress varies linearly across the height, peaking at the outer fibers where the section modulus is evaluated.

Worked Example

For a beam with \(b = 50\) mm and \(h = 100\) mm: $$S = \frac{50 \times 100^{2}}{6} = \frac{500000}{6} \approx 83{,}333.33 \text{ mm}^{3}.$$ The moment of inertia is $$I = \frac{50 \times 100^{3}}{12} = \frac{50{,}000{,}000}{12} \approx 4{,}166{,}666.67 \text{ mm}^{4}.$$

FAQ

Which dimension is the height? The height h is the dimension parallel to the direction of the applied bending (the depth of the beam). Swapping b and h gives the section modulus for bending about the other axis.

Does this work for any unit? Yes — it is pure geometry. Just keep b and h in the same length unit; results scale accordingly (length³ for S, length⁴ for I).

What is the difference between elastic and plastic section modulus? This tool computes the elastic section modulus used in elastic bending. The plastic section modulus (\(Z = b \cdot h^{2} / 4\)) applies when the entire section yields.

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