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Formula

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Results

Rectangle Width
1,920
same units as height
Height 1,080
Width ÷ Height ratio 1.7778

What this calculator does

This tool finds the width of a rectangle when you already know its height and the aspect ratio you want to keep. Aspect ratio describes the proportional relationship between width and height — for example 16:9 for widescreen video, 4:3 for older displays, or 3:2 for many photographs. By locking the ratio and supplying one dimension, the other is fully determined.

How to use it

Enter the rectangle's height in any unit (pixels, centimetres, inches — the result comes back in the same unit). Then type the two parts of the aspect ratio: the width part in "Aspect Ratio Width" and the height part in "Aspect Ratio Height". For a 16:9 frame you would enter 16 and 9. Press calculate and the matching width appears instantly.

The formula explained

The calculation is a single proportion:

$$\text{Width} = \text{Height} \times \frac{\text{Aspect Ratio Width}}{\text{Aspect Ratio Height}}$$

The fraction \(ar_w \div ar_h\) is the ratio of width to height. Multiplying the known height by that ratio scales it up (or down) to the correct width while preserving the shape. If the aspect-ratio height is zero the ratio is undefined, so the tool guards against division by zero.

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Rectangle showing height h, width w and aspect ratio components
Width is found by scaling the height by the ratio of aspect-ratio width to aspect-ratio height.

Worked example

Suppose you have a video that is 1080 pixels tall and you want it to be 16:9. Then $$w = 1080 \times (16 \div 9) = 1080 \times 1.7778 = 1920 \text{ pixels}$$ — the familiar 1920×1080 Full HD frame.

Three rectangles of equal height but different aspect ratios giving different widths
For a fixed height, wider aspect ratios produce wider rectangles.

FAQ

Can I use decimals? Yes. Both the height and the ratio values accept decimals, so a 2.39:1 cinema ratio works fine.

What units does the width use? The same units as the height you entered — the ratio itself is unitless.

How do I go the other way? To find height from a known width, rearrange to \(h = w \times (ar_h \div ar_w)\). Use a width-to-height variant for that.

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