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Relative Humidity
50.3
%
Saturation vapour pressure at dry bulb es(T) 31.67 hPa
Saturation vapour pressure at wet bulb es(Tw) 20.63 hPa
Actual vapour pressure e 15.93 hPa

What this calculator does

A psychrometer uses two thermometers — a dry bulb that measures the ordinary air temperature and a wet bulb wrapped in a moist wick. Evaporation from the wick cools the wet bulb, and the size of that cooling depends on how dry the air is. This calculator converts those two readings into relative humidity (RH), the percentage of moisture the air holds relative to the maximum it could hold at the dry-bulb temperature.

Sling psychrometer with two thermometers, one bulb wrapped in a wet wick
A psychrometer pairs a dry-bulb thermometer with a wet-bulb thermometer whose bulb is kept moist.

How to use it

Enter the dry-bulb temperature, the wet-bulb temperature (always equal to or lower than the dry bulb), and the local atmospheric pressure in hectopascals (sea-level standard is 1013.25 hPa). The tool returns the relative humidity along with the saturation vapour pressures and the actual vapour pressure of the air.

The formula explained

The result uses the psychrometric equation:

$$RH = 100 \times \frac{e_{s}(T_w) - A \cdot P \cdot (T - T_w)}{e_{s}(T)}$$

where \(T\) is the dry-bulb temperature, \(T_w\) the wet-bulb temperature, \(P\) the pressure, and \(A \approx 0.000662\ \text{°C}^{-1}\) the psychrometer constant. The saturation vapour pressure \(e_{s}\) at any temperature \(t\) (°C) comes from the Magnus–Tetens relation $$e_{s}(t) = 6.112 \cdot \exp\!\left(\frac{17.67 \cdot t}{t + 243.5}\right)$$ in hPa.

Curve of saturation vapour pressure rising with temperature, with wet and dry bulb points marked
Saturation vapour pressure rises steeply with temperature; the wet-bulb depression drives the humidity calculation.

Worked example

For \(T = 25\,\text{°C}\), \(T_w = 18\,\text{°C}\), \(P = 1013.25\,\text{hPa}\): \(e_{s}(25) \approx 31.67\,\text{hPa}\) and \(e_{s}(18) \approx 20.62\,\text{hPa}\). The actual vapour pressure $$e = 20.62 - 0.000662 \times 1013.25 \times (25 - 18) \approx 20.62 - 4.70 = 15.93\,\text{hPa}.$$ So $$RH = 100 \times \frac{15.93}{31.67} \approx 50.3\%.$$

FAQ

Why must the wet bulb be cooler? Evaporation removes heat, so unless the air is fully saturated the wet bulb always reads lower; if the readings are equal, RH is 100%.

What pressure should I enter? Use your local station pressure if known; otherwise the standard 1013.25 hPa is a good approximation near sea level.

How accurate is it? The psychrometer constant assumes a properly ventilated (aspirated) wet bulb; poor airflow can bias results, so results are accurate to a few percent in normal conditions.

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