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Value of the Term
216
T(r+1) = C(n,r)·a^(n−r)·b^r
Binomial coefficient C(n, r) 6
r index (k − 1) 2
Exponent on a (n − r) 2
Exponent on b (r) 2

What Is the Binomial Expansion Term Calculator?

This calculator finds a single specific term in the binomial expansion of \((a + b)^n\) without expanding the whole expression. Whether you need the 5th term, the constant term, or the coefficient of a particular power, the general-term formula gives it directly. This is a universal mathematics tool — it applies anywhere, with no country-specific rules.

How to Use It

Enter the first base value a, the second base value b, the exponent n, and the term position k (1 for the first term, 2 for the second, and so on). The calculator returns the binomial coefficient \(C(n, r)\), the value of the term, and the underlying exponents. Note that the kth term uses \(r = k - 1\).

The Formula Explained

The general term in the expansion of \((a + b)^n\) is:

$$T_{r+1} = \binom{n}{r} \cdot a^{\,n-r} \cdot b^{\,r}$$

Here \(C(n, r) = \dfrac{n!}{r!\,(n-r)!}\) is the binomial coefficient. The kth term corresponds to \(r = k - 1\), so the first term has \(r = 0\) and the last term has \(r = n\). The exponents always sum to \(n\): \((n - r) + r = n\).

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Diagram labeling the parts of the binomial term formula
Each part of T(r+1)=C(n,r)·a^(n−r)·b^r identified by color-coded labels.

Worked Example

Find the 3rd term of \((2 + 3)^4\). Here \(a = 2\), \(b = 3\), \(n = 4\), \(k = 3\), so \(r = 2\). The coefficient is \(C(4, 2) = 6\). The term is $$6 \cdot 2^{\,4-2} \cdot 3^2 = 6 \cdot 4 \cdot 9 = 216.$$

Pascal's triangle highlighting one coefficient row
Binomial coefficients form Pascal's triangle; the kth term picks one entry from row n.

Pascal's Triangle / Binomial Coefficient Table

The entries below are the binomial coefficients \(\binom{n}{r}\). To find the \(k\)th term of an expansion, read along row \(n\) and take the value in column \(r=k-1\) (columns are numbered starting at 0). For example, the 4th term of \((a+b)^6\) uses \(r=3\), giving \(\binom{6}{3}=20\).

n r=0 r=1 r=2 r=3 r=4 r=5 r=6 r=7 r=8 r=9 r=10
0 1
1 1 1
2 1 2 1
3 1 3 3 1
4 1 4 6 4 1
5 1 5 10 10 5 1
6 1 6 15 20 15 6 1
7 1 7 21 35 35 21 7 1
8 1 8 28 56 70 56 28 8 1
9 1 9 36 84 126 126 84 36 9 1
10 1 10 45 120 210 252 210 120 45 10 1

Each entry equals the sum of the two entries above it, and each row is symmetric: \(\binom{n}{r}=\binom{n}{n-r}\).

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Definitions & Glossary

\(a\) — first term (base)
The leading expression inside the binomial \((a+b)^n\). In each term it is raised to the power \(n-r\).
\(b\) — second term (base)
The trailing expression inside the binomial. In each term it is raised to the power \(r\). It may be negative or a reciprocal (e.g. \(1/x\)); its sign and form carry through to the term value.
\(n\) — exponent (degree)
The power to which the binomial is raised. The full expansion has \(n+1\) terms, and the exponents on \(a\) and \(b\) in each term always sum to \(n\).
\(k\) — term number
The position of the term you want, counted from 1 (the first term, \(a^n\), is \(k=1\)). Valid values run from \(1\) to \(n+1\).
\(r\) — coefficient index
The zero-based index used in the binomial coefficient and powers, defined by \(r=k-1\). It is also the power on \(b\).
\(T_{r+1}\) — general term
The formula for the \((r+1)\)th term of the expansion: \(T_{r+1}=\binom{n}{r}\,a^{\,n-r}\,b^{\,r}\). Setting \(r=k-1\) gives the \(k\)th term.
\(\binom{n}{r}\) — binomial coefficient
Read "\(n\) choose \(r\)", it counts the ways to choose \(r\) items from \(n\) and is computed as \(\binom{n}{r}=\dfrac{n!}{r!\,(n-r)!}\). It is the numerical coefficient (before any sign from \(a\) or \(b\)) of the term.

FAQ

What does k mean? \(k\) is the term number counting from 1. The kth term uses \(r = k - 1\) in the formula.

How do I find the constant term? For expressions like \((x + 1/x)^n\), set the net power of \(x\) to zero and solve for \(r\), then use that \(r\) (\(k = r + 1\)) here.

Can a and b be negative or fractional? Yes — the calculator evaluates \(a^{\,n-r} \cdot b^{\,r}\) numerically, so negatives and decimals work.

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