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Curie Constant
20,764.8905
K·m³  (χ = C / T)
Number density N 10,000,000,000,000,000,000,000,000,000 m⁻³
Magnetic moment μ 0 J/T
Boltzmann constant k_B 0 J/K

What Is the Curie Constant?

The Curie constant (\(C\)) is a material-specific quantity in Curie's law of paramagnetism, which states that the magnetic susceptibility of a paramagnet is inversely proportional to temperature: \(\chi = C / T\). The constant depends on the density of magnetic moments and the size of each moment. This calculator is a universal physics tool — it applies anywhere and uses SI units throughout.

Curie law graph showing susceptibility decreasing with temperature and inverse susceptibility rising linearly
The Curie law: susceptibility \(\chi\) falls as \(1/T\), so the inverse \(1/\chi\) is a straight line whose slope is set by the Curie constant.

How to Use the Calculator

Enter three values: the number density of magnetic moments \(N\) (number of moments per cubic metre), the effective magnetic moment \(\mu\) of each entity (in joules per tesla, J/T), and the Boltzmann constant \(k_B\) (pre-filled with the exact SI value \(1.380649\times10^{-23}\) J/K). Press calculate to obtain the Curie constant in K·m³, which feeds directly into \(\chi = C/T\).

The Formula Explained

The Curie constant is given by $$C = \frac{N \cdot \mu^{2}}{3 \, k_B}$$ Here \(N \cdot \mu^2\) captures the total magnetic response per unit volume, the factor 3 comes from averaging the moment orientation over all directions in three-dimensional space, and dividing by the thermal energy scale \(k_B\) links the alignment of moments to temperature. A larger moment or denser packing raises \(C\); thermal agitation (\(k_B\)) lowers it.

Array of randomly oriented magnetic moment arrows representing paramagnetic dipoles in a field
Paramagnetism arises from many magnetic moments \(\mu\) that partly align with an external field \(H\).

Worked Example

Suppose \(N = 1\times10^{28}\) moments/m³ and \(\mu = 9.274\times10^{-24}\) J/T (about one Bohr magneton). Then $$\mu^{2} = 8.6007\times10^{-47}, \quad N \cdot \mu^{2} = 8.6007\times10^{-19},$$ and dividing by \(3 \cdot k_B = 4.141947\times10^{-23}\) gives $$C \approx 2.0765\times10^{4} \ \text{K}\cdot\text{m}^3.$$ You can then predict susceptibility at any temperature as \(\chi = C/T\).

FAQ

What units does this use? Strict SI: \(N\) in m⁻³, \(\mu\) in J/T, \(k_B\) in J/K, giving \(C\) in K·m³.

What is the effective magnetic moment? For an ion it is \(\mu = g \cdot \sqrt{J(J+1)} \cdot \mu_B\), where \(\mu_B = 9.274\times10^{-24}\) J/T is the Bohr magneton.

Why divide by 3? The factor of 3 arises from the orientational (thermal) average of the projection of the moment along the applied field in three dimensions.

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