What Is Scalar Multiplication of a Matrix?
Scalar multiplication is one of the most fundamental operations in linear algebra. When you multiply a matrix A by a single number (a scalar) c, you simply multiply every individual entry of the matrix by that number. The result is a new matrix of exactly the same dimensions, where each element has been scaled by c. This calculator works with 2×2 matrices, the most common size used in classrooms, geometry, and introductory algebra.
How to Use This Calculator
Enter the scalar value c in the first field. Then fill in the four entries of your 2×2 matrix A: the top row (a11, a12) and the bottom row (a21, a22). Click calculate and the tool returns the scaled matrix cA, with every element multiplied by your scalar. Negative scalars and decimals are fully supported.
The Formula Explained
The rule is written compactly as $$(cA)_{ij} = c \times A_{ij}$$ The subscript ij refers to the entry in row i and column j. So for a 2×2 matrix the four resulting entries are \(c\cdot a_{11}\), \(c\cdot a_{12}\), \(c\cdot a_{21}\), and \(c\cdot a_{22}\). No row or column mixing occurs — each entry is handled independently.
$$\text{c} \cdot \begin{bmatrix} a_{11} & a_{12} \\ a_{21} & a_{22} \end{bmatrix} = \begin{bmatrix} \text{c}\,a_{11} & \text{c}\,a_{12} \\ \text{c}\,a_{21} & \text{c}\,a_{22} \end{bmatrix}$$
Worked Example
Suppose \(c = 3\) and \(A = \begin{bmatrix} 1 & 2 \\ 3 & 4 \end{bmatrix}\). Multiplying each entry by 3 gives $$3 \cdot \begin{bmatrix} 1 & 2 \\ 3 & 4 \end{bmatrix} = \begin{bmatrix} 3 & 6 \\ 9 & 12 \end{bmatrix}$$ Notice that the structure of the matrix is unchanged; only the magnitude of each entry grows by the factor 3.
FAQ
Does scalar multiplication change the size of the matrix? No. The result always has the same number of rows and columns as the original.
What happens with a scalar of 0? Every entry becomes 0, producing the zero matrix.
Can the scalar be negative or fractional? Yes. A negative scalar flips the sign of every entry, and fractional scalars shrink the entries proportionally.