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Formula

Show calculation steps (3)
  1. Perimeter

    Perimeter: Rhombus Area, Perimeter and Vertex Angles from Diagonals

    Perimeter from the diagonals via the side length.

  2. Vertex Angle A

    Vertex Angle A: Rhombus Area, Perimeter and Vertex Angles from Diagonals

    Angle facing diagonal b, in degrees.

  3. Vertex Angle B

    Vertex Angle B: Rhombus Area, Perimeter and Vertex Angles from Diagonals

    Angle facing diagonal a, in degrees.

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Results

Area S
3
square units
Perimeter L 7.211103 units
Vertex angle θa 112.6199°
Vertex angle θb 67.3801°

What this calculator does

A rhombus is a quadrilateral with four equal sides. Its two diagonals are perpendicular and bisect each other, which means knowing just the two diagonal lengths is enough to fully describe the shape. This tool takes the diagonals a and b (in any consistent length unit) and returns the area, the perimeter, and both interior vertex angles. This is pure geometry, so it applies identically anywhere with no country-specific rules.

Rhombus with its two perpendicular diagonals a and b crossing at the center
A rhombus with diagonals a and b meeting at right angles at the center.

How to use it

Enter the length of diagonal a and diagonal b using the same unit for both (for example centimetres, metres, or inches). Both must be greater than zero. The area is reported in the square of that unit, the perimeter in the same unit, and the two angles in degrees.

The formulas explained

Because the diagonals cross at right angles and bisect one another, each half-diagonal is \(a/2\) and \(b/2\), so the side length is $$s = \sqrt{\left(\frac{a}{2}\right)^{2} + \left(\frac{b}{2}\right)^{2}} = \frac{1}{2}\cdot\sqrt{a^{2}+b^{2}}.$$

  • Area: $$S = \frac{a \cdot b}{2}$$
  • Perimeter: $$L = 4s = 2\cdot\sqrt{a^{2} + b^{2}}$$
  • Vertex angle on diagonal a: $$\theta_a = 2\cdot\arctan\!\left(\frac{b}{a}\right)$$
  • Vertex angle on diagonal b: $$\theta_b = 2\cdot\arctan\!\left(\frac{a}{b}\right)$$

The two angles are supplementary, so \(\theta_a + \theta_b\) always equals \(180\degree\).

Rhombus divided into four right triangles by its diagonals, showing half-diagonals, side L and a vertex angle
The diagonals split the rhombus into four right triangles, giving the side length and vertex angles.

Worked example

For \(a = 2\) and \(b = 3\): $$S = \frac{2\cdot 3}{2} = 3 \text{ square units}.$$ $$L = 2\cdot\sqrt{4 + 9} = 2\cdot\sqrt{13} \approx 7.2111 \text{ units}.$$ $$\theta_a = 2\cdot\arctan\!\left(\frac{3}{2}\right) \approx 112.6199\degree$$ and $$\theta_b = 2\cdot\arctan\!\left(\frac{2}{3}\right) \approx 67.3801\degree.$$ Their sum is exactly \(180\degree\).

FAQ

What if the two diagonals are equal? The rhombus becomes a square: the area is \(a^{2}/2\) and both vertex angles are \(90\degree\).

What units should I use? Any unit, as long as both diagonals share it. The output area is in that unit squared and the perimeter in the same unit.

Why are there two angles? A rhombus has two pairs of equal opposite angles. The pair at the vertices lying on diagonal a equals \(\theta_a\), and the other pair equals \(\theta_b = 180\degree - \theta_a\).

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