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  1. Parallel Capacitance

    Parallel Capacitance: Series and Parallel Capacitance Calculator

    Capacitors in parallel; capacitances add directly.

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Results

Series circuit Cs
75
uF
Parallel circuit Cp 400 uF
Series formula Cs = (C1 × C2) / (C1 + C2)
Parallel formula Cp = C1 + C2

What this calculator does

This tool computes the equivalent (combined) capacitance of two capacitors for the two basic wiring arrangements: series and parallel. Capacitance combination is universal physics, so the same formulas apply everywhere with no regional rules. Pick a unit (farad, millifarad, microfarad, nanofarad, picofarad or femtofarad) and the answers come back in that same unit.

How to use it

Enter the value of the first capacitor in the "Capacitance C1" field and the second in "Capacitance C2". Choose a single unit from the dropdown - it applies to both inputs. The calculator returns the series combination Cs and the parallel combination Cp, expressed in the unit you selected.

The formula explained

For two capacitors in series, charge must pass through both, so their reciprocals add: \(\frac{1}{C_s} = \frac{1}{C_1} + \frac{1}{C_2}\), which simplifies to

$$C_{series} = \frac{\text{C}_1 \cdot \text{C}_2}{\text{C}_1 + \text{C}_2}$$

The result is always smaller than the smaller of the two capacitors. For two capacitors in parallel, the plate areas effectively add, so

$$C_{parallel} = \text{C}_1 + \text{C}_2$$

always larger than either one. Because both inputs share the same unit, the unit factor cancels in the series ratio and factors out of the parallel sum, so the outputs are reported directly in the input unit.

Parallel-plate illustration showing series increases gap and parallel increases area
Intuition: series behaves like a larger gap (less capacitance); parallel like more plate area (more capacitance).
Circuit diagram of two capacitors in series and the same two capacitors in parallel
Two capacitors connected in series (left) versus in parallel (right).

Worked example

Take \(C_1 = 100\ \text{uF}\) and \(C_2 = 300\ \text{uF}\). Series:

$$C_s = \frac{100 \times 300}{100 + 300} = \frac{30000}{400} = 75\ \text{uF}$$

Parallel:

$$C_p = 100 + 300 = 400\ \text{uF}$$

Notice the series value (75 uF) is below the smaller capacitor (100 uF), while the parallel value (400 uF) exceeds both.

FAQ

Why is series capacitance smaller? Stacking capacitors in series increases the effective plate separation, which lowers capacitance - the reciprocal sum guarantees Cs is below the smallest capacitor.

What if one capacitor is zero? A zero (or open) capacitor in series blocks charge, so Cs = 0. In parallel, Cp simply equals the non-zero capacitor.

Do the units have to match? Yes - this calculator uses one unit for both inputs, and the outputs are given in that same unit.

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