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Impedance |Z|
329.690831
ohms
Phase angle φ 72.343213 degrees
Inductive reactance XL 314.159265 ohms
Angular frequency ω 31,415.926536 rad/s

What is an RL Series Circuit?

An RL series circuit is an electrical network in which a resistor (R) and an inductor (L) are connected end to end so the same current flows through both. When driven by a sinusoidal source at frequency f, the inductor opposes changes in current and introduces a frequency-dependent reactance. This calculator finds the total impedance magnitude |Z| and the phase angle between voltage and current.

Series RL circuit with a resistor and inductor connected to an AC source
A series RL circuit: a resistor (R) and inductor (L) driven by an AC source.

How to Use It

Enter the resistance, inductance, and frequency, choosing a unit for each from its dropdown. All values are converted to SI base units (ohms, henries, hertz) before the math runs. Press calculate to see the impedance in ohms, the phase angle in degrees, the inductive reactance, and the angular frequency.

The Formula Explained

First the angular frequency is found: \(\omega = 2\pi f\). The inductive reactance is \(X_L = \omega L\). Because the resistor and inductor voltages are 90 degrees out of phase, the impedance is the vector sum:

$$|Z| = \sqrt{R^{2} + X_L^{2}}$$

The phase angle, by which the source voltage leads the current, is

$$\varphi = \arctan\!\left(\frac{X_L}{R}\right)$$

reported in degrees and lying between 0 and 90.

Impedance triangle showing resistance, inductive reactance and total impedance
The impedance triangle: R and inductive reactance (2πfL) combine into the impedance magnitude |Z| at phase angle θ.

Worked Example

With \(R = 100\ \Omega\), \(L = 10\ \text{mH}\ (0.01\ \text{H})\), and \(f = 5\ \text{kHz}\ (5000\ \text{Hz})\):

$$\omega = 2\pi \times 5000 = 31415.93\ \text{rad/s}$$$$X_L = 31415.93 \times 0.01 = 314.159\ \Omega$$

Then

$$|Z| = \sqrt{100^{2} + 314.159^{2}} = \sqrt{108696.04} = 329.691\ \Omega$$

and

$$\varphi = \arctan(3.14159) = 72.343^{\circ}$$

FAQ

What happens at DC (f = 0)? The reactance vanishes, so \(|Z| = R\) and the phase angle is \(0^{\circ}\).

What if resistance is zero (pure inductor)? Then \(|Z| = \omega L\) and the phase angle is exactly \(90^{\circ}\); the calculator handles this safely using a two-argument arctangent.

Does increasing frequency raise the impedance? Yes. Higher frequency increases \(X_L\), which increases \(|Z|\) and pushes the phase angle toward \(90^{\circ}\).

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