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Cement Required
6.34
bags (≈ 316.8 kg)
Total dry volume 1.54
Cement volume 0.22
Sand volume 0.44
Gravel volume 0.88

What is the Concrete Mix Ratio Calculator?

This calculator estimates how much cement, sand and gravel you need to produce a given volume of concrete using a chosen volumetric mix ratio such as 1:2:4 (cement:sand:gravel). It converts the finished (wet) volume into the larger dry material volume and splits that dry volume among the three ingredients according to their ratio parts. It works with any unit system as long as you enter volume in cubic metres.

Three buckets showing concrete proportions of cement, sand and gravel in a 1:2:4 ratio
A concrete mix ratio describes the proportion of cement, sand and gravel by volume.

How to use it

Enter the wet concrete volume you want to place in cubic metres. Then enter the ratio parts for cement, sand and gravel — a common general-purpose mix is 1:2:4, while structural concrete often uses 1:1.5:3. Finally set the cement bag weight (typically 50 kg, or 94 lb ≈ 42.6 kg in the US). The tool returns the dry volume, the volume of each material, the total cement mass, and the number of bags.

The formula explained

Fresh concrete contains water and air voids, so a batch of dry materials shrinks when mixed and compacted. The industry rule of thumb multiplies the wet volume by 1.54 to obtain the required dry volume. Each ingredient then gets a fraction equal to its ratio part divided by the sum of all parts:

$$V_i = V_{dry} \times \frac{r_i}{\Sigma r}$$

Cement mass uses a bulk density of about 1440 kg/m³, and bags are mass divided by bag weight.

$$\begin{gathered} \text{Bags} = \frac{V_{dry}\cdot\dfrac{\text{Cement}}{S}\times 1440}{\text{Bag Weight (kg)}} \\[1.5em] \text{where}\quad \left\{ \begin{aligned} V_{dry} &= \text{Volume (m}^3\text{)} \times 1.54 \\ S &= \text{Cement} + \text{Sand} + \text{Gravel} \end{aligned} \right. \end{gathered}$$
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Diagram showing wet concrete volume expanding to a larger dry volume via the 1.54 factor
The dry-volume factor of 1.54 accounts for voids and shrinkage when mixing dry materials.

Worked example

For 1 m³ of concrete at a 1:2:4 ratio: dry volume =

$$1 \times 1.54 = 1.54 \text{ m}^3$$

The ratio sum is 7.

$$\text{Cement volume} = 1.54 \times \frac{1}{7} = 0.22 \text{ m}^3$$$$\text{sand} = 1.54 \times \frac{2}{7} = 0.44 \text{ m}^3$$$$\text{gravel} = 1.54 \times \frac{4}{7} = 0.88 \text{ m}^3$$

Cement mass =

$$0.22 \times 1440 \approx 316.8 \text{ kg}$$

which is

$$316.8 / 50 \approx 6.34 \text{ bags}$$

FAQ

Why 1.54? It accounts for the bulking and voids between dry aggregate particles that disappear once mixed with water and compacted. Some engineers use 1.50–1.57.

Does this include water? No. Water is added by water-cement ratio (often 0.4–0.6 of cement weight) and is not part of the dry volume split.

Can I use 1:1.5:3? Yes — enter those parts directly; the calculator handles any positive ratio values.

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