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  1. Energy Released (Joules)

    Energy Released (Joules): Earthquake Magnitude Difference & Energy Ratio Comparison Calculator

    Energy of each quake in joules, E = 10^(4.8 + 1.5 x Magnitude)

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Results

Energy ratio (Ja / Jb)
44.67
times the energy of earthquake B
Magnitude difference (ΔM = Ma − Mb) 1.1
Seismic energy of A (Ja) 199.5262E16 J
Seismic energy of B (Jb) 4.466836E16 J

What this calculator does

This tool compares two earthquakes by their magnitude and by the seismic energy they release. Magnitude is a logarithmic scale, so a small difference in magnitude corresponds to a huge difference in energy. Enter the magnitude of earthquake A and earthquake B, and the calculator returns the magnitude difference (\(\Delta M\)) and the energy ratio (\(J_a / J_b\)), plus the absolute seismic energy of each event in joules. This is a pure physics/seismology calculation and applies identically anywhere in the world.

The formula explained

The calculator uses the standard Gutenberg-Richter energy relation in base-10 logarithmic form: \(\log_{10}(J) = 4.8 + 1.5\cdot M\), where \(J\) is the seismic energy in joules and \(M\) is the magnitude. Rearranged,

$$J = 10^{\,4.8 + 1.5M}$$

When you take the ratio of two earthquakes, the constant 4.8 cancels, leaving

$$\frac{J_a}{J_b} = 10^{\,1.5\cdot(M_a - M_b)} = 10^{\,1.5\cdot\Delta M}$$

A useful rule of thumb: each whole step up in magnitude multiplies energy by about \(10^{1.5} \approx 32\) times, and two steps multiply it by \(10^3 = 1000\) times. Note that 1 joule = 1 \(\text{N}\cdot\text{m}\).

Exponential curve of seismic energy versus earthquake magnitude
Seismic energy grows exponentially with magnitude, following \(\log_{10}(J)=4.8+1.5M\).
Two earthquakes compared with their energy bars on a logarithmic scale, showing energy ratio from magnitude difference
A one-unit magnitude increase corresponds to about 32 times more seismic energy.

Worked example

Compare a magnitude 9.0 earthquake (A) with a magnitude 7.9 earthquake (B). The magnitude difference is

$$\Delta M = 9.0 - 7.9 = 1.1$$

The energy ratio is

$$10^{\,1.5 \times 1.1} = 10^{1.65} \approx 44.7$$

so earthquake A releases roughly 45 times the energy of earthquake B. The absolute energies are

$$J_a = 10^{\,4.8 + 13.5} = 10^{18.3} \approx 2.0\times10^{18}\ \text{J}$$$$J_b = 10^{\,4.8 + 11.85} = 10^{16.65} \approx 4.5\times10^{16}\ \text{J}$$

Dividing them back confirms the same ratio.

FAQ

Why is a magnitude 9 so much stronger than a magnitude 7? Because energy grows by a factor of about 32 per magnitude unit. A two-unit difference means about 1000 times more energy released.

What if both magnitudes are equal? Then \(\Delta M = 0\) and the energy ratio is \(10^0 = 1\), meaning equal energy.

What if A is smaller than B? The magnitude difference is negative and the energy ratio is less than 1, indicating earthquake A is the weaker of the two.

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