MCP๋กœ ์—ฐ๊ฒฐ โ†’

๊ณ„์‚ฐ ์ž…๋ ฅ

๊ณต์‹

๊ด‘๊ณ 

๊ฒฐ๊ณผ

์‚ผ๊ฐํ˜• ๋„“์ด
50
์ œ๊ณฑ ๋‹จ์œ„
๋ฐ‘๋ณ€ ๊ธธ์ด 10
๋น—๋ณ€ 14.1421
๋‘˜๋ ˆ 34.1421

45-45-90 ์‚ผ๊ฐํ˜•์ด๋ž€?

45-45-90 ์‚ผ๊ฐํ˜•์€ ์ง๊ฐ์ด๋“ฑ๋ณ€์‚ผ๊ฐํ˜•์ž…๋‹ˆ๋‹ค. ํ•˜๋‚˜์˜ 90ยฐ ๊ฐ๊ณผ ๋‘ ๊ฐœ์˜ ๋™์ผํ•œ 45ยฐ ๊ฐ์œผ๋กœ ์ด๋ฃจ์–ด์ ธ ์žˆ์ฃ . ๋‘ ์˜ˆ๊ฐ์ด ๊ฐ™๊ธฐ ๋•Œ๋ฌธ์— ์ง๊ฐ์„ ๋ผ๊ณ  ์žˆ๋Š” ๋‘ ๋ณ€, ์ฆ‰ ๋ฐ‘๋ณ€(๋‹ค๋ฆฌ)์˜ ๊ธธ์ด๋„ ์„œ๋กœ ๊ฐ™์Šต๋‹ˆ๋‹ค. ๋น—๋ณ€์€ ์–ธ์ œ๋‚˜ ๋ฐ‘๋ณ€ ๊ธธ์ด์— \(\sqrt{2}\)๋ฅผ ๊ณฑํ•œ ๊ฐ’์ด ๋ฉ๋‹ˆ๋‹ค. ์ด๋ ‡๊ฒŒ ๋น„์œจ์ด ๊ณ ์ •๋˜์–ด ์žˆ์–ด, ๋‹จ ํ•˜๋‚˜์˜ ๊ธธ์ด๋งŒ ์•Œ์•„๋„ ๋„“์ด๋ฅผ ์†์‰ฝ๊ฒŒ ๊ตฌํ•  ์ˆ˜ ์žˆ์Šต๋‹ˆ๋‹ค.

๋‘ ๊ฐœ์˜ 45๋„ ๊ฐ์„ ๊ฐ€์ง„ 45-45-90 ์ง๊ฐ ์ด๋“ฑ๋ณ€์‚ผ๊ฐํ˜•, ๊ฐ™์€ ๋ณ€ a์™€ ๋น—๋ณ€ c
45-45-90 ์‚ผ๊ฐํ˜•์€ ๋‘ ๋ณ€์˜ ๊ธธ์ด๊ฐ€ ๊ฐ™๊ณ  ๊ทธ ์‚ฌ์ด์— ์ง๊ฐ์ด ์žˆ์Šต๋‹ˆ๋‹ค.

๊ณ„์‚ฐ๊ธฐ ์‚ฌ์šฉ ๋ฐฉ๋ฒ•

๋จผ์ € ์•Œ๊ณ  ์žˆ๋Š” ๊ฐ’์ด ๋ฐ‘๋ณ€์ธ์ง€ ๋น—๋ณ€์ธ์ง€ ์„ ํƒํ•˜์„ธ์š”. ๊ทธ๋Ÿฐ ๋‹ค์Œ ํ•ด๋‹น ๋ณ€์˜ ๊ธธ์ด๋ฅผ ์ž…๋ ฅํ•˜๋ฉด ๋„“์ด๊ฐ€ ๋ฐ”๋กœ ํ‘œ์‹œ๋ฉ๋‹ˆ๋‹ค. ๋‚˜๋จธ์ง€ ํ•œ ๋ณ€์˜ ๊ธธ์ด์™€ ์ „์ฒด ๋‘˜๋ ˆ๋„ ํ•จ๊ป˜ ์•Œ๋ ค์ฃผ๋ฏ€๋กœ ๊ณ„์‚ฐ ๊ฒฐ๊ณผ๋ฅผ ์‰ฝ๊ฒŒ ํ™•์ธํ•  ์ˆ˜ ์žˆ์Šต๋‹ˆ๋‹ค. ๋ชจ๋“  ๊ฐ’์€ ์ž…๋ ฅํ•œ ๋‹จ์œ„ ๊ทธ๋Œ€๋กœ ํ‘œ์‹œ๋˜๋ฉฐ, ๋„“์ด๋Š” ์ œ๊ณฑ ๋‹จ์œ„๋กœ ๋‚˜ํƒ€๋‚ฉ๋‹ˆ๋‹ค.

๊ณต์‹ ํ’€์ด

45-45-90 ์‚ผ๊ฐํ˜•์€ ๋‘ ๋ฐ‘๋ณ€์˜ ๊ธธ์ด๊ฐ€ ๊ฐ™์œผ๋ฏ€๋กœ, ์ผ๋ฐ˜์ ์ธ ์‚ผ๊ฐํ˜• ๋„“์ด ๊ณต์‹์ธ \(\frac{1}{2} \times \text{๋ฐ‘๋ณ€} \times \text{๋†’์ด}\)๊ฐ€ \(\frac{1}{2} \times \text{๋ฐ‘๋ณ€} \times \text{๋ฐ‘๋ณ€}\)์œผ๋กœ ์ •๋ฆฌ๋ฉ๋‹ˆ๋‹ค. ๋”ฐ๋ผ์„œ ๋‹ค์Œ๊ณผ ๊ฐ™์ด ๋ฉ๋‹ˆ๋‹ค.

$$A = \dfrac{\text{๋ฐ‘๋ณ€}^2}{2}$$

๋งŒ์•ฝ ๋น—๋ณ€๋งŒ ์•Œ๊ณ  ์žˆ๋‹ค๋ฉด, \(\text{๋น—๋ณ€} = \text{๋ฐ‘๋ณ€} \cdot \sqrt{2}\) ์ด๋ฏ€๋กœ \(\text{๋ฐ‘๋ณ€}^2 = \frac{\text{๋น—๋ณ€}^2}{2}\) ๋ผ๋Š” ๊ด€๊ณ„๊ฐ€ ์„ฑ๋ฆฝํ•ฉ๋‹ˆ๋‹ค. ์ด๋ฅผ ๋Œ€์ž…ํ•˜๋ฉด ๋‹ค์Œ ๊ณต์‹์„ ์–ป์„ ์ˆ˜ ์žˆ์Šต๋‹ˆ๋‹ค.

$$A = \dfrac{\text{๋น—๋ณ€}^2}{4}$$

๋Œ€๊ฐ์„ ์œผ๋กœ ๋‘ ๊ฐœ์˜ ๋™์ผํ•œ 45-45-90 ์‚ผ๊ฐํ˜•์œผ๋กœ ๋‚˜๋‰œ ์ •์‚ฌ๊ฐํ˜•, ๋„“์ด๊ฐ€ ์ •์‚ฌ๊ฐํ˜•์˜ ์ ˆ๋ฐ˜์ž„์„ ๋ณด์—ฌ์คŒ
์ด ์‚ผ๊ฐํ˜•์€ ์ •์‚ฌ๊ฐํ˜•์˜ ์ ˆ๋ฐ˜์ด๋ฏ€๋กœ \(A = \frac{\text{๋ณ€}^2}{2}\)์ž…๋‹ˆ๋‹ค.

์˜ˆ์ œ๋กœ ์‚ดํŽด๋ณด๊ธฐ

๊ฐ ๋ฐ‘๋ณ€์˜ ๊ธธ์ด๊ฐ€ 10 ๋‹จ์œ„๋ผ๊ณ  ๊ฐ€์ •ํ•ด ๋ด…์‹œ๋‹ค. ๊ทธ๋Ÿฌ๋ฉด ๋‹ค์Œ๊ณผ ๊ฐ™์Šต๋‹ˆ๋‹ค.

$$A = \dfrac{10^2}{2} = \dfrac{100}{2} = 50 \text{ ์ œ๊ณฑ ๋‹จ์œ„}$$

๋น—๋ณ€์€ \(10 \cdot \sqrt{2} \approx 14.142\) ์ด๊ณ , ๋‘˜๋ ˆ๋Š” \(10 + 10 + 14.142 \approx 34.142\) ๋‹จ์œ„์ž…๋‹ˆ๋‹ค. ๋ฐ˜๋Œ€๋กœ ๋น—๋ณ€์ด 14.142๋ผ๋Š” ๊ฒƒ๋งŒ ์•Œ๊ณ  ์žˆ๋‹ค๋ฉด, \(A = \frac{14.142^2}{4} \approx \frac{200}{4} = 50\) ์œผ๋กœ ๋™์ผํ•œ ๊ฒฐ๊ณผ๊ฐ€ ๋‚˜์˜ต๋‹ˆ๋‹ค.

์ž์ฃผ ๋ฌป๋Š” ์งˆ๋ฌธ

์™œ ๋‘ ๋ฐ‘๋ณ€์˜ ๊ธธ์ด๊ฐ€ ๊ฐ™๋‚˜์š”? ์ง๊ฐ์ด ์•„๋‹Œ ๋‘ ๊ฐ์ด ๋ชจ๋‘ 45ยฐ๋กœ ๊ฐ™๊ธฐ ๋•Œ๋ฌธ์—, ๊ทธ ๊ฐ์˜ ๋งž์€ํŽธ ๋ณ€๋“ค๋„ ๊ธธ์ด๊ฐ€ ๊ฐ™์•„์ ธ ์ด๋“ฑ๋ณ€์‚ผ๊ฐํ˜•์ด ๋ฉ๋‹ˆ๋‹ค.

์„ธ ๋ณ€์˜ ๋น„์œจ์€ ์–ด๋–ป๊ฒŒ ๋˜๋‚˜์š”? ์„ธ ๋ณ€์€ ์–ธ์ œ๋‚˜ \(1 : 1 : \sqrt{2}\) (๋ฐ‘๋ณ€ : ๋ฐ‘๋ณ€ : ๋น—๋ณ€) ์˜ ๋น„์œจ์„ ์ด๋ฃน๋‹ˆ๋‹ค.

์–ด๋–ค ๋‹จ์œ„๋“  ์‚ฌ์šฉํ•  ์ˆ˜ ์žˆ๋‚˜์š”? ๋„ค, ๊ฐ€๋Šฅํ•ฉ๋‹ˆ๋‹ค. ์–ด๋–ค ๋‹จ์œ„๋กœ๋“  ๊ธธ์ด๋ฅผ ์ž…๋ ฅํ•˜๋ฉด, ๋„“์ด๋Š” ๊ทธ ๋‹จ์œ„๋ฅผ ์ œ๊ณฑํ•œ ๊ฐ’์œผ๋กœ ํ‘œ์‹œ๋ฉ๋‹ˆ๋‹ค.

์ตœ์ข… ์—…๋ฐ์ดํŠธ: