MCP๋กœ ์—ฐ๊ฒฐ โ†’

๊ณ„์‚ฐ ์ž…๋ ฅ

Solves the equation aยทx + b = cยทx + d.

๊ณต์‹

๊ด‘๊ณ 

๊ฒฐ๊ณผ

ํ•ด
x = 2
Unique solution
๋ฐฉ์ •์‹ aยทx + b = cยทx + d
์ •๋ฆฌํ•œ ์‹ x = (d โˆ’ b) / (a โˆ’ c)
a โˆ’ c 2

์–ด๋–ค ๊ณ„์‚ฐ๊ธฐ์ธ๊ฐ€์š”?

์ด ๊ณ„์‚ฐ๊ธฐ๋Š” ๋ฏธ์ง€์ˆ˜๊ฐ€ ์–‘๋ณ€์— ๋ชจ๋‘ ๋“ค์–ด ์žˆ๋Š” ์ผ์ฐจ๋ฐฉ์ •์‹, ์ฆ‰ \(\text{a}\cdot x + \text{b} = \text{c}\cdot x + \text{d}\) ๊ผด์˜ ์‹์„ ํ’€์–ด ์ค๋‹ˆ๋‹ค. x์˜ ๋‘ ๊ณ„์ˆ˜์™€ ๋‘ ์ƒ์ˆ˜ํ•ญ, ์ด๋ ‡๊ฒŒ ๋„ค ๊ฐœ์˜ ์ˆซ์ž๋งŒ ์ž…๋ ฅํ•˜๋ฉด x์˜ ์ •ํ™•ํ•œ ๊ฐ’์€ ๋ฌผ๋ก  ์‹์„ ์ •๋ฆฌํ•˜๋Š” ๊ณต์‹๊ณผ ์ค‘๊ฐ„ ํ’€์ด ๊ณผ์ •๊นŒ์ง€ ํ•จ๊ป˜ ๋ณด์—ฌ ์ค๋‹ˆ๋‹ค. ํ•ด๊ฐ€ ์—†๊ฑฐ๋‚˜ ํ•ด๊ฐ€ ๋ฌด์ˆ˜ํžˆ ๋งŽ์€ ํŠน์ˆ˜ํ•œ ๊ฒฝ์šฐ๋„ ์ž๋™์œผ๋กœ ํŒ๋ณ„ํ•ฉ๋‹ˆ๋‹ค.

์‚ฌ์šฉ ๋ฐฉ๋ฒ•

๋จผ์ € ๋ฐฉ์ •์‹์„ \(\text{a}\cdot x + \text{b} = \text{c}\cdot x + \text{d}\) ํ˜•ํƒœ์— ๋งž๊ฒŒ ์ •๋ฆฌํ•˜์„ธ์š”. ์˜ˆ๋ฅผ ๋“ค์–ด \(3x + 5 = x + 9\) ๋ผ๋ฉด \(\text{a} = 3\), \(\text{b} = 5\), \(\text{c} = 1\), \(\text{d} = 9\) ๊ฐ€ ๋ฉ๋‹ˆ๋‹ค. ์ด ๋„ค ๊ฐ’์„ ์ž…๋ ฅํ•˜๋ฉด ๋ฐ”๋กœ ๋‹ต์„ ํ™•์ธํ•  ์ˆ˜ ์žˆ์Šต๋‹ˆ๋‹ค. ๊ณ„์ˆ˜์™€ ์ƒ์ˆ˜์—๋Š” ์Œ์ˆ˜๋‚˜ ์†Œ์ˆ˜๋ฅผ ๋„ฃ์–ด๋„ ๋ฉ๋‹ˆ๋‹ค.

๊ณต์‹ ์„ค๋ช…

\(\text{a}\cdot x + \text{b} = \text{c}\cdot x + \text{d}\) ์—์„œ ์ถœ๋ฐœํ•ด ์–‘๋ณ€์—์„œ \(\text{c}\cdot x\) ๋ฅผ ๋นผ๋ฉด ๋ฏธ์ง€์ˆ˜ ํ•ญ์„ ํ•œ์ชฝ์œผ๋กœ ๋ชจ์„ ์ˆ˜ ์žˆ์Šต๋‹ˆ๋‹ค: \((\text{a} - \text{c})\cdot x + \text{b} = \text{d}\). ์ด์–ด์„œ ์–‘๋ณ€์—์„œ \(\text{b}\) ๋ฅผ ๋นผ๋ฉด \((\text{a} - \text{c})\cdot x = \text{d} - \text{b}\) ๊ฐ€ ๋ฉ๋‹ˆ๋‹ค. ๋งˆ์ง€๋ง‰์œผ๋กœ \((\text{a} - \text{c})\) ๋กœ ๋‚˜๋ˆ„๋ฉด ๋‹ค์Œ๊ณผ ๊ฐ™์Šต๋‹ˆ๋‹ค.

$$x = \frac{\text{d} - \text{b}}{\text{a} - \text{c}}$$

์ด ๋‚˜๋ˆ—์…ˆ์€ \(\text{a} - \text{c}\) ๊ฐ€ 0์ด ์•„๋‹ ๋•Œ๋งŒ ์„ฑ๋ฆฝํ•ฉ๋‹ˆ๋‹ค. ๋งŒ์•ฝ \(\text{a} = \text{c}\) ์ด๊ณ  \(\text{b} = \text{d}\) ๋ผ๋ฉด, ์ด ๋ฐฉ์ •์‹์€ ๋ชจ๋“  x์— ๋Œ€ํ•ด ํ•ญ์ƒ ์ฐธ์ธ ํ•ญ๋“ฑ์‹์ด ๋˜์–ด ํ•ด๊ฐ€ ๋ฌด์ˆ˜ํžˆ ๋งŽ์Šต๋‹ˆ๋‹ค. ๋ฐ˜๋Œ€๋กœ \(\text{a} = \text{c}\) ์ด์ง€๋งŒ \(\text{b} \neq \text{d}\) ๋ผ๋ฉด ๋ชจ์ˆœ์ด ๋ฐœ์ƒํ•ด ํ•ด๊ฐ€ ์—†์Šต๋‹ˆ๋‹ค.

๊ด‘๊ณ 
x๋ฅผ ๋ถ„๋ฆฌํ•˜๊ธฐ ์œ„ํ•ด ํ•ญ์ด ๋“ฑํ˜ธ๋ฅผ ๋„˜์–ด ์ด๋™ํ•˜๋Š” ๊ฒƒ์„ ๋ณด์—ฌ์ฃผ๋Š” ๋„ํ‘œ
ax + b = cx + d๋ฅผ ํ’€๋ ค๋ฉด ๋ณ€์ˆ˜ ํ•ญ์€ ํ•œ์ชฝ์—, ์ƒ์ˆ˜๋Š” ๋‹ค๋ฅธ ์ชฝ์— ๋ชจ์œผ์„ธ์š”.

ํ’€์ด ์˜ˆ์‹œ

\(3x + 5 = x + 9\) ๋ฅผ ํ’€์–ด ๋ณด๊ฒ ์Šต๋‹ˆ๋‹ค. ์—ฌ๊ธฐ์„œ \(\text{a} = 3\), \(\text{b} = 5\), \(\text{c} = 1\), \(\text{d} = 9\) ์ž…๋‹ˆ๋‹ค. ๋”ฐ๋ผ์„œ $$x = \frac{9 - 5}{3 - 1} = \frac{4}{2} = 2$$ ๊ฐ€ ๋ฉ๋‹ˆ๋‹ค. ๊ฒ€์‚ฐํ•ด ๋ณด๋ฉด \(3(2) + 5 = 11\), \(1(2) + 9 = 11\) ๋กœ ์–‘๋ณ€์ด ๋ชจ๋‘ 11๋กœ ๊ฐ™์Šต๋‹ˆ๋‹ค. ๊ทธ๋Ÿฌ๋ฏ€๋กœ \(x = 2\) ์ž…๋‹ˆ๋‹ค.

ํ•œ์ชฝ ์ ‘์‹œ์— x ํ•ญ, ๋‹ค๋ฅธ ์ชฝ์— ์ˆซ์ž๋ฅผ ์˜ฌ๋ฆฌ๊ณ  ๊ท ํ˜•์„ ์œ ์ง€ํ•˜๋Š” ์ €์šธ
๋ฐฉ์ •์‹์€ ๊ท ํ˜• ์žกํžŒ ์ €์šธ๊ณผ ๊ฐ™์•„์„œ, ์–‘์ชฝ์— ๊ฐ™์€ ์—ฐ์‚ฐ์„ ํ•˜๋ฉด ๊ท ํ˜•์ด ์œ ์ง€๋ฉ๋‹ˆ๋‹ค.

์ž์ฃผ ๋ฌป๋Š” ์งˆ๋ฌธ

๋ฐฉ์ •์‹์˜ ํ•ญ ์ˆœ์„œ๊ฐ€ ๋‹ค๋ฅด๋ฉด ์–ด๋–ป๊ฒŒ ํ•˜๋‚˜์š”? ๋จผ์ € ๋™๋ฅ˜ํ•ญ์„ ์ •๋ฆฌํ•ด์„œ ์–‘์ชฝ์ด ๊ฐ๊ฐ xํ•ญ ํ•˜๋‚˜์™€ ์ƒ์ˆ˜ํ•ญ ํ•˜๋‚˜๋กœ ๊น”๋”ํ•˜๊ฒŒ ์ •๋ฆฌ๋œ ๋‹ค์Œ์— ๊ฐ’์„ ์ž…๋ ฅํ•˜์„ธ์š”.

์™œ "ํ•ด๊ฐ€ ์—†์Œ"์ด ๋‚˜์˜ค๋‚˜์š”? \(\text{a}\) ์™€ \(\text{c}\) ๊ฐ€ ๊ฐ™์ง€๋งŒ \(\text{b}\) ์™€ \(\text{d}\) ๊ฐ€ ๋‹ค๋ฅผ ๋•Œ ์ด๋Ÿฐ ๊ฒฐ๊ณผ๊ฐ€ ๋‚˜์˜ต๋‹ˆ๋‹ค. xํ•ญ์ด ์„œ๋กœ ์†Œ๊ฑฐ๋˜๋ฉด์„œ \(5 = 9\) ๊ฐ™์€ ๊ฑฐ์ง“ ๋“ฑ์‹๋งŒ ๋‚จ๊ธฐ ๋•Œ๋ฌธ์ž…๋‹ˆ๋‹ค.

์†Œ์ˆ˜๋‚˜ ์Œ์ˆ˜๋„ ๊ณ„์‚ฐํ•  ์ˆ˜ ์žˆ๋‚˜์š”? ๋„ค. \(\text{a} = -2.5\) ๋‚˜ \(\text{d} = 0\) ๊ฐ™์€ ๊ฐ’๋„ ์ž…๋ ฅํ•  ์ˆ˜ ์žˆ์Šต๋‹ˆ๋‹ค. \(\text{a} - \text{c} \neq 0\) ์ด๊ธฐ๋งŒ ํ•˜๋ฉด ์–ด๋–ค ์‹ค์ˆ˜์— ๋Œ€ํ•ด์„œ๋„ ๊ณต์‹์ด ๊ทธ๋Œ€๋กœ ์ ์šฉ๋ฉ๋‹ˆ๋‹ค.

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