MCP๋กœ ์—ฐ๊ฒฐ โ†’

๊ณ„์‚ฐ ์ž…๋ ฅ

๊ณต์‹

Show calculation steps (2)
  1. Triangle Area (Heron Formula)

    Triangle Area (Heron Formula): ์‚ผ๊ฐํ˜• ๋‚ด์ ‘์›(๋‚ด์‹ฌ์›) ๋ฐ˜์ง€๋ฆ„ยท๋„“์ด ๊ณ„์‚ฐ๊ธฐ

    Area of the triangle from its three sides using Heron formula, with s the semi-perimeter.

  2. Incircle Area

    Incircle Area: ์‚ผ๊ฐํ˜• ๋‚ด์ ‘์›(๋‚ด์‹ฌ์›) ๋ฐ˜์ง€๋ฆ„ยท๋„“์ด ๊ณ„์‚ฐ๊ธฐ

    Area of the inscribed circle using the inradius r.

๊ด‘๊ณ 

๊ฒฐ๊ณผ

๋‚ด์ ‘์› ๋ฐ˜์ง€๋ฆ„ r
1
๊ธธ์ด (L)
Incircle diameter ฯ† 2 L
๋‚ด์ ‘์› ๋„“์ด Sc 3.141593 Lยฒ
์‚ผ๊ฐํ˜• ๋„“์ด St 6 Lยฒ
๋„“์ด ๋น„์œจ Sc/St 0.523599

์ด ๊ณ„์‚ฐ๊ธฐ๋กœ ๋ฌด์—‡์„ ํ•  ์ˆ˜ ์žˆ๋‚˜์š”

์ด ๋„๊ตฌ๋Š” ์„ธ ๋ณ€์˜ ๊ธธ์ด๋งŒ ์•Œ๋ฉด ์–ด๋–ค ์‚ผ๊ฐํ˜•์ด๋“  ๋‚ด์ ‘์›(๋‚ด์‹ฌ์›)์„ ๊ตฌํ•ด ์ค๋‹ˆ๋‹ค. ๋‚ด์ ‘์›์€ ์‚ผ๊ฐํ˜• ์•ˆ์— ๊ผญ ๋“ค์–ด๋งž๋Š” ๊ฐ€์žฅ ํฐ ์›์œผ๋กœ, ์„ธ ๋ณ€์— ๋ชจ๋‘ ์ ‘ํ•˜๋ฉฐ ๊ทธ ์ค‘์‹ฌ์ด ๋ฐ”๋กœ ๋‚ด์‹ฌ์ž…๋‹ˆ๋‹ค. ๊ณ„์‚ฐ๊ธฐ๋Š” ๋‚ด์ ‘์› ๋ฐ˜์ง€๋ฆ„(\(r\)), ์ง€๋ฆ„, ๋‚ด์ ‘์› ๋„“์ด, ์‚ผ๊ฐํ˜• ๋„“์ด, ๊ทธ๋ฆฌ๊ณ  ๋‚ด์ ‘์› ๋„“์ด์™€ ์‚ผ๊ฐํ˜• ๋„“์ด์˜ ๋น„์œจ์„ ํ•จ๊ป˜ ๋ณด์—ฌ ์ค๋‹ˆ๋‹ค. ์„ธ ๋ณ€์€ ๋ชจ๋‘ ๊ฐ™์€ ๋‹จ์œ„ "L"๋กœ ์ž…๋ ฅํ•ด์•ผ ํ•˜๋ฉฐ, ๋ฐ˜์ง€๋ฆ„๊ณผ ์ง€๋ฆ„์€ L ๋‹จ์œ„๋กœ, ๋„“์ด๋Š” Lยฒ ๋‹จ์œ„๋กœ ๋‚˜์˜ต๋‹ˆ๋‹ค. ๋ณ„๋„์˜ ๋‹จ์œ„ ๋ณ€ํ™˜์€ ์ ์šฉ๋˜์ง€ ์•Š์Šต๋‹ˆ๋‹ค.

์„ธ ๋ณ€์— ๋ชจ๋‘ ์ ‘ํ•˜๋Š” ๋‚ด์ ‘์›์„ ๊ฐ€์ง„ ์‚ผ๊ฐํ˜•์œผ๋กœ, ๋‚ด์‹ฌ์—์„œ ํ•œ ๋ณ€๊นŒ์ง€์˜ ๋‚ด์ ‘์› ๋ฐ˜์ง€๋ฆ„์„ ๋ณด์—ฌ ์คŒ
๋‚ด์ ‘์›์€ ์‚ผ๊ฐํ˜• ์•ˆ์— ๋”ฑ ๋งž๊ฒŒ ๋“ค์–ด๊ฐ€ ์„ธ ๋ณ€์— ๊ฐ๊ฐ ํ•œ ์ ์—์„œ ์ ‘ํ•ฉ๋‹ˆ๋‹ค. \(r\)์€ ๊ทธ ๋ฐ˜์ง€๋ฆ„์ž…๋‹ˆ๋‹ค.

์‚ฌ์šฉ ๋ฐฉ๋ฒ•

์„ธ ๋ณ€์˜ ๊ธธ์ด \(a\), \(b\), \(c\)๋ฅผ ์ž…๋ ฅํ•˜์„ธ์š”. ์„ธ ๊ฐ’์€ ๋ชจ๋‘ ์–‘์ˆ˜์—ฌ์•ผ ํ•˜๊ณ  ์‚ผ๊ฐํ˜• ๋ถ€๋“ฑ์‹์„ ๋งŒ์กฑํ•ด์•ผ ํ•ฉ๋‹ˆ๋‹ค. ์ฆ‰, ์–ด๋А ํ•œ ๋ณ€๋„ ๋‚˜๋จธ์ง€ ๋‘ ๋ณ€์˜ ํ•ฉ๋ณด๋‹ค ๋ฐ˜๋“œ์‹œ ์ž‘์•„์•ผ ํ•ฉ๋‹ˆ๋‹ค. ์œ ํšจํ•œ ์‚ผ๊ฐํ˜•์ด ๋งŒ๋“ค์–ด์ง€์ง€ ์•Š์œผ๋ฉด ๊ณ„์‚ฐ๊ธฐ๋Š” ์˜๋ฏธ ์—†๋Š” ๊ฐ’์„ ๋‚ด๋†“๋Š” ๋Œ€์‹  ์˜ค๋ฅ˜๋ฅผ ์•Œ๋ ค ์ค๋‹ˆ๋‹ค.

๊ณต์‹ ์‚ดํŽด๋ณด๊ธฐ

๋จผ์ € ๋ฐ˜๋‘˜๋ ˆ \(s = (a + b + c) / 2\)๋ฅผ ๊ตฌํ•ฉ๋‹ˆ๋‹ค. ํ—ค๋ก ์˜ ๊ณต์‹์œผ๋กœ ์‚ผ๊ฐํ˜• ๋„“์ด $$S_t = \sqrt{s(s-a)(s-b)(s-c)}$$ ๋ฅผ ์–ป์Šต๋‹ˆ๋‹ค. ๋‚ด์ ‘์› ๋ฐ˜์ง€๋ฆ„์€ ์ด ๋„“์ด๋ฅผ ๋ฐ˜๋‘˜๋ ˆ๋กœ ๋‚˜๋ˆˆ ๊ฐ’์œผ๋กœ ๊ฐ„๋‹จํžˆ \(r = S_t / s\)์ž…๋‹ˆ๋‹ค. ์—ฌ๊ธฐ์„œ ์ง€๋ฆ„์€ \(\phi = 2r\), ๋‚ด์ ‘์› ๋„“์ด๋Š” \(S_c = \pi r^2\), ๋„“์ด ๋น„์œจ์€ \(S_c / S_t\)๋กœ ๊ตฌํ•ด์ง‘๋‹ˆ๋‹ค.

๋‚ด์ ‘์›์˜ ์ค‘์‹ฌ์„ ์‚ผ๊ฐํ˜•์˜ ์„ธ ๊ฐ ์ด๋“ฑ๋ถ„์„ ์˜ ๊ต์ ์œผ๋กœ ๋‚˜ํƒ€๋‚ธ ๊ทธ๋ฆผ
๋‚ด์‹ฌ์€ ์„ธ ๊ฐ์˜ ์ด๋“ฑ๋ถ„์„ ์ด ๋งŒ๋‚˜๋Š” ๊ณณ์— ์žˆ์œผ๋ฉฐ, ๋‚ด์ ‘์› ๋ฐ˜์ง€๋ฆ„์€ ๋„“์ด๋ฅผ ๋ฐ˜๋‘˜๋ ˆ๋กœ ๋‚˜๋ˆˆ ๊ฐ’๊ณผ ๊ฐ™์Šต๋‹ˆ๋‹ค.

๊ณ„์‚ฐ ์˜ˆ์‹œ

๋Œ€ํ‘œ์ ์ธ 3-4-5 ์ง๊ฐ์‚ผ๊ฐํ˜•์„ ์‚ดํŽด๋ด…์‹œ๋‹ค. $$s = (3+4+5)/2 = 6$$ $$S_t = \sqrt{6 \cdot 3 \cdot 2 \cdot 1} = \sqrt{36} = 6$$ ๋”ฐ๋ผ์„œ \(r = 6/6 = 1\), ์ง€๋ฆ„ \(= 2\), ๋‚ด์ ‘์› ๋„“์ด \(= \pi \cdot 1^2 \approx 3.14159\), ๋„“์ด ๋น„์œจ \(= 3.14159 / 6 \approx 0.5236\)์ด ๋ฉ๋‹ˆ๋‹ค.

์ž์ฃผ ๋ฌป๋Š” ์งˆ๋ฌธ

๋‚ด์ ‘์›์ด๋ž€ ๋ฌด์—‡์ธ๊ฐ€์š”? ์‚ผ๊ฐํ˜• ์•ˆ์—์„œ ์„ธ ๋ณ€์— ๋ชจ๋‘ ์ ‘ํ•˜๋Š” ์œ ์ผํ•œ ์›์ž…๋‹ˆ๋‹ค. ๊ทธ ์ค‘์‹ฌ์€ ์„ธ ๊ฐ์˜ ์ด๋“ฑ๋ถ„์„ ์ด ๋งŒ๋‚˜๋Š” ์ ์ธ ๋‚ด์‹ฌ์ž…๋‹ˆ๋‹ค.

์™œ ์˜ค๋ฅ˜๊ฐ€ ๋‚˜๋‚˜์š”? ์ž…๋ ฅํ•œ ๋ณ€๋“ค์ด ์‹ค์ œ ์‚ผ๊ฐํ˜•์„ ์ด๋ฃจ์ง€ ๋ชปํ•˜๊ธฐ ๋•Œ๋ฌธ์ž…๋‹ˆ๋‹ค. ์–ด๋–ค ๋ณ€์ด 0์ด๊ฑฐ๋‚˜ ์Œ์ˆ˜์ด๊ฑฐ๋‚˜, ํ•œ ๋ณ€์ด ๋‚˜๋จธ์ง€ ๋‘ ๋ณ€์„ ํ•ฉํ•œ ๊ฒƒ๋ณด๋‹ค ๊ธธ๋ฉด ์‚ผ๊ฐํ˜•์ด ์„ฑ๋ฆฝํ•˜์ง€ ์•Š์Šต๋‹ˆ๋‹ค.

์–ด๋–ค ์‚ผ๊ฐํ˜•์ด๋“  ๊ณ„์‚ฐ๋˜๋‚˜์š”? ๋„ค, ์‚ผ๊ฐํ˜• ๋ถ€๋“ฑ์‹๋งŒ ๋งŒ์กฑํ•˜๋ฉด ๋ถ€๋“ฑ๋ณ€์‚ผ๊ฐํ˜•, ์ด๋“ฑ๋ณ€์‚ผ๊ฐํ˜•, ์ •์‚ผ๊ฐํ˜•, ์ง๊ฐ์‚ผ๊ฐํ˜• ๋ชจ๋‘ ๊ณ„์‚ฐํ•  ์ˆ˜ ์žˆ์Šต๋‹ˆ๋‹ค.

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