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Equation of the Circle
(x − 1)² + (y − 7)² = 25
standard form (x − h)² + (y − k)² = r²
Center (h, k) (1, 7)
Radius (r) 5
Diameter 10
25

What this calculator does

Given the two endpoints of a circle's diameter, this tool finds the complete standard-form equation of the circle, \((x - h)^2 + (y - k)^2 = r^2\). It also reports the center (h, k), the radius r, the full diameter length, and r² (the right-hand side of the equation). It is a pure geometry tool that works for any pair of points in the coordinate plane.

How to use it

Enter the coordinates of the first diameter endpoint as (x₁, y₁) and the second as (x₂, y₂). Negative and decimal values are allowed. Press calculate to see the equation and all supporting values. The two points must be distinct — identical points produce a degenerate circle of radius 0.

The formula explained

A diameter passes through the center, so the center is exactly the midpoint of the two endpoints: \(h = \dfrac{x_1 + x_2}{2}\) and \(k = \dfrac{y_1 + y_2}{2}\). The diameter's length is the distance between the endpoints, found with the distance formula \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\). The radius is half of that. Substituting the center and r² into the equation gives:

$$\begin{gathered} (x-h)^2 + (y-k)^2 = r^2 \\[1.5em] \text{where}\quad \left\{ \begin{aligned} h &= \dfrac{\text{x}_1 + \text{x}_2}{2} \\ k &= \dfrac{\text{y}_1 + \text{y}_2}{2} \\ r &= \dfrac{\sqrt{\left(\text{x}_2 - \text{x}_1\right)^2 + \left(\text{y}_2 - \text{y}_1\right)^2}}{2} \end{aligned} \right. \end{gathered}$$
Circle with two diameter endpoints, center as midpoint, and radius shown
The center is the midpoint of the diameter endpoints, and the radius is half the distance between them.

Worked example

Endpoints (−2, 3) and (4, 11). Center: \(\left(\dfrac{-2+4}{2}, \dfrac{3+11}{2}\right) = (1, 7)\). Diameter:

$$\text{Diameter} = \sqrt{(4-(-2))^2 + (11-3)^2} = \sqrt{36 + 64} = \sqrt{100} = 10$$

so \(r = 5\) and \(r^2 = 25\). The equation is:

$$(x - 1)^2 + (y - 7)^2 = 25$$

FAQ

What if the endpoints are the same point? The radius is 0 and the "circle" is a single point; the equation becomes \((x - h)^2 + (y - k)^2 = 0\).

Does the order of the points matter? No. The midpoint and distance are symmetric, so swapping the endpoints gives the same circle.

Can I use negative or decimal coordinates? Yes — any real numbers work, including negatives and fractions/decimals.

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