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Triangle Area
15.1554
square units
Side a 5
Side b 7
Included angle C 60°
Formula Area = ½ · a · b · sin(C)

What is the SAS Triangle Area Calculator?

This tool computes the area of any triangle when you know two side lengths and the angle between them — the "Side-Angle-Side" (SAS) case. It is a universal geometry formula that works for every triangle, no matter its shape, and avoids the need to first find the height.

How to use it

Enter the lengths of the two sides, a and b, then enter the included angle C in degrees — that is the angle formed where the two sides meet. The calculator returns the area in the same square units as your side measurements (e.g. cm in gives cm²).

The formula explained

The area equals one half the product of the two sides multiplied by the sine of the included angle: $$\text{Area} = \frac{1}{2} \cdot \text{Side }a \cdot \text{Side }b \cdot \sin\!\left(\text{Angle }C\right)$$ The sine term effectively projects one side onto the perpendicular height. Because sine peaks at 90°, a right angle between the two sides gives the largest possible area for those side lengths.

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Triangle with two sides a and b and the included angle C between them
The SAS setup: two known sides a and b with the included angle C between them.

Worked example

Suppose \(a = 5\), \(b = 7\), and \(C = 60°\). Then \(\sin(60°) \approx 0.866025\). $$\text{Area} = 0.5 \times 5 \times 7 \times 0.866025 = 17.5 \times 0.866025 \approx 15.155$$ square units.

Triangle showing base b, slant side a, and dashed height h equal to a times sine of C
Why the formula works: the height equals \(a \cdot \sin(C)\), giving \(\text{Area} = \frac{1}{2} \cdot b \cdot (a \cdot \sin C)\).

FAQ

Does the angle have to be in degrees? Yes — enter C in degrees; the calculator converts it to radians internally.

What if I only know all three sides? Use Heron's formula instead; this calculator needs exactly two sides and their included angle.

Can the angle be 90°? Yes. At 90° the formula reduces to \(\frac{1}{2} \cdot a \cdot b\), the familiar right-triangle area.

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