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Total Delta-V (Δv)
3,542.08
m/s
Delta-V (km/s) 3.542 km/s
Mass Ratio (wet / dry) 3.333
Propellant Mass 7,000 kg

What Is the Tsiolkovsky Rocket Equation?

The Tsiolkovsky rocket equation, derived by Konstantin Tsiolkovsky in 1903, describes the maximum change in velocity (delta-v, or \(\Delta v\)) a rocket can achieve given its propellant and engine performance. Delta-v is the single most important number in mission planning: reaching low Earth orbit, transferring to the Moon, or landing on Mars each require a known \(\Delta v\) budget. This calculator is a universal physics tool — it works for any rocket regardless of country or manufacturer.

Diagram of a rocket showing wet mass, dry mass, and exhaust producing delta-v
The rocket equation relates a vehicle's mass change from burning propellant to the velocity it gains.

How to Use This Calculator

Enter four values: the engine's specific impulse (Isp) in seconds, the standard gravity g₀ (use 9.80665 m/s² by convention), the wet mass (the rocket fully fueled, in kg), and the dry mass (the rocket after all propellant is burned, in kg). The calculator returns total delta-v in both m/s and km/s, the mass ratio, and the propellant mass consumed.

The Formula Explained

$$\Delta v = \text{Isp} \cdot g_0 \cdot \ln\!\left(\frac{\text{Wet Mass}}{\text{Dry Mass}}\right)$$ The term \(\text{Isp} \cdot g_0\) is the effective exhaust velocity (\(v_e\)), measured in m/s. The natural logarithm of the mass ratio captures the diminishing returns of carrying more fuel — doubling propellant does not double \(\Delta v\). A higher Isp engine or a lighter dry mass both increase the achievable \(\Delta v\).

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Curve showing delta-v rising with the mass ratio on a logarithmic relationship
Delta-v grows with the natural logarithm of the wet-to-dry mass ratio, so gains diminish as the ratio increases.

Worked Example

Suppose Isp = 300 s, g₀ = 9.80665 m/s², wet mass = 10,000 kg, and dry mass = 3,000 kg. The mass ratio is \(10{,}000 / 3{,}000 = 3.3333\), and \(\ln(3.3333) \approx 1.20397\). Then $$\Delta v = 300 \times 9.80665 \times 1.20397 \approx 3542.2 \ \text{m/s} \approx 3.54 \ \text{km/s}$$

FAQ

What is a typical delta-v budget? Reaching low Earth orbit needs roughly 9.4 km/s including losses; an Earth-to-Mars transfer adds several more km/s.

Why use g₀ = 9.80665? Specific impulse in seconds is defined relative to standard gravity, so g₀ is a fixed constant, not the local gravity at your launch site.

What if I know exhaust velocity instead of Isp? Divide your exhaust velocity by g₀ to get the equivalent Isp, then enter that value.

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