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Enter Calculation

Formula

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Results

Area
12.5
square units
Leg (each equal side) 5
Hypotenuse 7.0711
Perimeter 17.0711

What is a 45-45-90 triangle?

A 45-45-90 triangle is a special right triangle whose angles measure 45°, 45° and 90°. Because two angles are equal, it is also an isosceles right triangle: the two legs (the sides next to the right angle) are exactly the same length. This fixed shape means all 45-45-90 triangles are similar, and their sides always follow the ratio \(x : x : x\sqrt{2}\).

Right triangle with two 45 degree angles and one 90 degree angle, two equal legs and a hypotenuse
A 45-45-90 triangle has two equal legs and angles of 45°, 45° and 90°.

How to use this calculator

Pick whether you know a leg (one of the two equal sides) or the hypotenuse (the longest side, opposite the right angle), then enter its length. The calculator instantly returns the missing side, the area and the perimeter — all in the same units you typed.

The formula explained

If a leg has length \(x\), the hypotenuse is \(x\sqrt{2}\) (about \(1.41421 \times x\)). Going the other way, a leg is the hypotenuse divided by \(\sqrt{2}\). The area of any triangle is \(\frac{1}{2} \times \text{base} \times \text{height}\); here both legs serve as base and height, so the area simplifies to \(\frac{x^2}{2}\). The perimeter is the sum of the three sides: \(2x + x\sqrt{2}\). The core relationships are:

$$\text{hypotenuse} = \text{leg} \times \sqrt{2}, \quad \text{Area} = \frac{\text{leg}^2}{2}$$
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45-45-90 triangle with legs labeled x and hypotenuse labeled x times square root of 2
The side ratio is \(x : x : x\sqrt{2}\) — each leg is \(x\) and the hypotenuse is \(x\sqrt{2}\).

Worked example

Suppose a leg = 5. The hypotenuse is

$$5 \times \sqrt{2} \approx 7.0711$$

The area is

$$\frac{5^2}{2} = 12.5 \text{ square units}$$

The perimeter is

$$2 \times 5 + 7.0711 = 17.0711 \text{ units}$$

FAQ

Why is the hypotenuse √2 times a leg? By the Pythagorean theorem, \(\text{hyp}^2 = x^2 + x^2 = 2x^2\), so \(\text{hyp} = x\sqrt{2}\).

Can I enter the hypotenuse instead of a leg? Yes — select "Hypotenuse" and each leg is computed as \(\text{value} \div \sqrt{2}\).

What units does it use? The tool is unit-agnostic; outputs share the units of your input (length for sides, those units squared for area).

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