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Formula

Show calculation steps (2)
  1. Median to Side b

    Median to Side b: Triangle Median Calculator

    Length of the median from the vertex opposite side b

  2. Median to Side c

    Median to Side c: Triangle Median Calculator

    Length of the median from the vertex opposite side c

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Results

Median to Side a (mₐ)
8.544
length units
Median to side a (mₐ) 8.544
Median to side b (m_b) 7.2111
Median to side c (m_c) 5

What is a Triangle Median?

A median of a triangle is a line segment joining a vertex to the midpoint of the opposite side. Every triangle has exactly three medians, and they all intersect at a single point called the centroid, which divides each median in a 2:1 ratio. This calculator computes the length of all three medians directly from the three side lengths a, b, and c.

Triangle with three medians drawn from each vertex to the midpoint of the opposite side, meeting at the centroid
The three medians of a triangle connect each vertex to the midpoint of the opposite side and intersect at the centroid.

How to Use the Calculator

Enter the three side lengths of your triangle into the fields labelled Side a, Side b, and Side c. Use any consistent unit (cm, m, inches — the result comes out in the same unit). Click calculate and you'll get the median to each side. The median ma is the one drawn to side a, mb to side b, and mc to side c.

The Formula Explained

The length of the median to side a is given by Apollonius's theorem:

$$m_a = \frac{1}{2}\sqrt{2b^{2} + 2c^{2} - a^{2}}$$

By symmetry, the other two medians swap the roles of the sides:

$$m_b = \frac{1}{2}\sqrt{2a^{2} + 2c^{2} - b^{2}} \quad \text{and} \quad m_c = \frac{1}{2}\sqrt{2a^{2} + 2b^{2} - c^{2}}$$

Notice that the median to side c uses the squares of sides a and b, NOT c — the side the median is drawn to is the one subtracted.

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Triangle with sides labeled a, b, c and one median m_a drawn to the midpoint of side a
Median m_a is computed from the side lengths a, b, and c using the median length formula.

Worked Example

For a right triangle with sides a = 6, b = 8, c = 10:

$$m_c = \frac{1}{2}\sqrt{2\cdot6^{2} + 2\cdot8^{2} - 10^{2}} = \frac{1}{2}\sqrt{72 + 128 - 100} = \frac{1}{2}\sqrt{100} = 5.$$

$$m_a = \frac{1}{2}\sqrt{2\cdot64 + 2\cdot100 - 36} = \frac{1}{2}\sqrt{292} \approx 8.544.$$

$$m_b = \frac{1}{2}\sqrt{2\cdot36 + 2\cdot100 - 64} = \frac{1}{2}\sqrt{208} \approx 7.211.$$

FAQ

Do the three medians always meet at one point? Yes — they always intersect at the centroid, which is the triangle's center of mass.

What if my values don't form a valid triangle? The expression under the square root must be positive. For impossible side combinations the calculator returns 0.

Is the median the same as the altitude or angle bisector? No. A median goes to the midpoint of the opposite side, while an altitude is perpendicular to it and an angle bisector splits the angle. They coincide only in special cases like equilateral triangles.

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