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Probability
16.67%
chance with two fair six-sided dice
Favorable outcomes 6
Total outcomes 36
Probability (decimal) 0.1667
Odds against 5 : 1

What is the Two Dice Probability Calculator?

When you roll two fair six-sided dice, there are \(6 \times 6 = 36\) equally likely ordered outcomes. This calculator counts how many of those outcomes match the condition you choose — equal to, less than, or greater than a target sum — and divides by 36 to give the exact probability. It works for any sum from 2 to 12.

How to use it

Enter a target sum between 2 and 12, pick a condition (exactly equal, less than, less than or equal, greater than, or greater than or equal), and read off the probability as a percentage, a decimal, and as odds against. The favorable and total outcome counts are shown so you can verify the result yourself.

The formula explained

The probability of a sum s is simply the number of ways to roll s divided by 36:

$$P = \frac{\left|\left\{(a,b) : a+b = \text{Target}\right\}\right|}{36}$$

The number of ways peaks at 7 (six combinations: 1-6, 2-5, 3-4, 4-3, 5-2, 6-1) and decreases symmetrically toward the extremes 2 and 12, which each have only one way. Order matters in the count, so 2-5 and 5-2 are treated as distinct outcomes.

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Bar chart of probabilities for sums 2 through 12 forming a triangular peak at 7
The distribution of two-dice sums peaks at 7, which has the most combinations (6 of 36).
Grid of all 36 outcomes from two dice with diagonal bands showing each sum
The 6x6 grid of 36 equally likely outcomes, with diagonals grouping rolls that share the same sum.

Worked example

What is the chance of rolling a sum of 7? There are 6 favorable outcomes out of 36, so

$$P = 6 / 36 = 0.1667 \approx 16.67\%$$

The odds against are \((36 - 6) / 6 = 5 : 1\).

FAQ

Why 36 outcomes and not 21? Each die is independent, so ordered pairs (1,2) and (2,1) are separate equally likely results. Using 36 keeps every outcome equally probable.

What sum is most likely? A sum of 7 is the most probable at \(6/36 \approx 16.67\%\), because it has the most combinations.

Does this assume fair dice? Yes — it assumes two standard, fair, six-sided dice with each face equally likely.

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